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KengaRu [80]
3 years ago
7

What would y be if 8x-6y=36

Mathematics
1 answer:
kondor19780726 [428]3 years ago
8 0

Answer:

\quad y=-\frac{2\left(-2x+9\right)}{3}

Step-by-step explanation:

1. Subtract 8x from both sides:

8x-6y-8x=36-8x

2. Simplify:

-6y=36-8x

3. Divide both sides by -6

\frac{-6y}{-6}=\frac{36}{-6}-\frac{8x}{-6}

4. Simplify to get answer

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Luda [366]
√896z^15/<span>√225z^6 

= </span>√896z^9/<span>√225

= </span>√64√14(z^4)<span>√z/15

= 8</span>√14(z^4)<span>√z/15

= (8z^4/15) * </span><span>√14z

x = 8</span>
7 0
3 years ago
A 100 serving of lasagna divided by 30 people
Misha Larkins [42]

Answer: 0.3

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Evaluate the expression (35+ 7) {6 – 5).
Fantom [35]

Answer:

The answer is 41

Step-by-step explanation:

(35 + 7) (6 - 5)

(42) × (1) = 41

Thus, The answer is 41

<u>-TheUnknownScientist</u>

8 0
2 years ago
CAN SOMEONE PLEASE HELP ME WITH THIS QUESTION
Murljashka [212]

Answer:

The value of DC is 66.34.

Step-by-step explanation:

The triangles ABC and DCA are right angled triangles.

The straight line AC is a bisector for angles C and A.

The measure of ∠C is 30°.

Then the measure of angles BCA and ACD will be 15° each.

The measure of angle DAB is 150°.

Then the measure of angles DAC and BAC will be 75° each.

Now consider the right angled triangle ABC.

The measure of side AC is:

AC^{2}=AB^{2}+BC^{2}\\AC=\sqrt{AB^{2}+BC^{2}}\\=\sqrt{4^{2}+(10\sqrt{3})^{2}}\\=\sqrt{316}

Consider the right angled triangle DCA.

The angle DAC measure 75°.

Using the trigonometric identities compute the value of Perpendicular DC as follows:

tan\ 75^{o}=\frac{DC}{\sqrt{316}}\\\\DC=3.732\times\sqrt{316}\\\\DC=66.34

Thus, the value of DC is 66.34.

7 0
3 years ago
The function h(t)=-4.87t^2+18.75t is used to model the height of an object projected in the air, where h(t) is the height in met
rodikova [14]
Looking at the graph you can see that the domain of the function is:
 [0, 3.85]
 To find the range of the function, we must follow the following steps:
 Step 1)
 
Evaluate for t = 0
 h (0) = - 4.87 (0) ^ 2 + 18.75 (0)
 h (0) = 0
 Step 2) 
 find the maximum of the function:
 h (t) = - 4.87t ^ 2 + 18.75t
 h '(t) = - 9.74 * t + 18.75
 -9.74 * t + 18.75 = 0
 t = 18.75 / 9.74
 t = 1.925051335
 We evaluate the function at its maximum point:
 h (1.925051335) = - 4.87 * (1.925051335) ^ 2 + 18.75 * (1.925051335)
 h (1.93) = 18.05
 The range of the function is:
 [0, 18.05]
 Answer:
 
Domain: [0, 3.85]
 Range: [0, 18.05]
 option 1
3 0
3 years ago
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