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Blababa [14]
3 years ago
14

After robbing a bank in dodge city, a robber gallops off at 14 mi/h. 20 minutes later, the marshall leaves to pursue the robber

at 16 mi/h. how long (in hours) does it take the marshall to catch up to the robber?
Mathematics
1 answer:
Morgarella [4.7K]3 years ago
4 0

For this case we have to write the equation of the position of each one.

We have then:

For the robber:

r = 14t

For the marshall :

r = 16 (t- (\frac{20}{60}))

r = 16 (t-\frac{1}{3})

By the time the marshall reaches the robber we have:

14t = 16 (t-\frac{1}{3})

From here, we clear the time.

We have then:

16t - 14t = \frac{16}{3}

2t = \frac{16}{3}

t =\frac{8}{3}

t = 2.7 h

Answer:

it takes the marshall to catch up to the robber about 2.7 hours.

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