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bekas [8.4K]
3 years ago
13

FRUIT Mason place 4 apples and oranges

Mathematics
1 answer:
nalin [4]3 years ago
7 0
He has made 8 full baskets with both apples and oranges together
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3c+2d=-24 and 2c+5d= -38
Assoli18 [71]

Answer:

c=-4, d=-6

Step-by-step explanation:

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3 years ago
Classify this triangle by the angles and lengths of sides shown.
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Can someone solve this
marysya [2.9K]

From the Arithmetic Information given, Pr = 0.049375 ≠ -8.050625 ≠ 0.0325  See explanation below.

<h3>

What are the step by steps solution to the questions above?</h3>

First, lets us restate the question properly. We have

Pr = 1 - ((6*12+6)/80)² = 1 - ((9*12²)/1600) - ((3*12*6)/1600) - (6²/6400) = 1 - 0.005625 * 12² - 0.001875 * 12 * 6 - 0.00015625 * 6²

Note that there are three equals signs. So lets divide the problem according and solve for the different parts.

Lets   1 - ((6*12+6)/80)²  ............A

1 - ((9*12²)/1600) - ((3*12*6)/1600) - (6²/6400) .............B; and

1 - 0.005625 * 12² - 0.001875 * 12 * 6 - 0.00015625 * 6² ........C

Solving for A we have

1 - (78/80)²

= 1 - (0.975)²

= 1 - 0.950625

A = 0.049375


Solving for B we have

1 - ((9*12²)/1600) - ((3*12*6)/1600) - (6²/6400)

= 1- (14,256/1600) - (216/1600) - (36/6400)
= 1 - 8.91 - 0.135 - 0.005625

B = -8.050625

Solving for C we have

1 - 0.005625 * 12² - 0.001875 * 12 * 6 - 0.00015625 * 6²

= 1 - 0.005625 * 144 - 0.001875 * 12 * 6 - 0.00015625 * 144

= 0.0325


In summary we can state that:

A = 0.049375

B =  -8.050625

C = 0.0325

Given that there were no abstract quantities, we can state that

Pr = A ≠ B ≠C or

Pr = 0.049375 ≠ -8.050625 ≠ 0.0325

Learn more about equations with equal signs at

brainly.com/question/18924248
#SPJ1

4 0
2 years ago
In order to test for the significance of a regression model involving 5 independent variables and 123 observations, the numerato
allochka39001 [22]

Answer: The numerator and denominator degrees of freedom (respectively) for the critical value of F are <u>4</u> and<u> 118 .</u>

Step-by-step explanation:

We know that , for critical value of F, degrees of freedom for numerator = k-1

and for denominator = n-k, where n= Total observations and k = number of independent variables.

Here, Numbers of independent variables(k) = 5

Total observations (n)= 123

So, Degrees of freedom for numerator  = 5-1=4

Degrees of freedom for denominator =123-5= 118

Hence, the numerator and denominator degrees of freedom (respectively) for the critical value of F are <u>4</u> and<u> 118 .</u>

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