Answer:
1
Step-by-step explanation:
6x+10=2x+14
6x-2x=14-10
4x=4
x=1
Answer:
out of 10?
Step-by-step explanation:
probably a 7-8? maybe 9?
Answer:
neither
Step-by-step explanation:
the correct answer should be ASA since 2 angles and 1 side is congruent
Remember, |n|≥0 for all real numbers n
so
-|x|=0
times -1
|x|=0
true, x=0, has a solution
|x|=-15
false, can't have negative absolute value
-|x|=12
|x|=-12
false, no negative absolute value
-|-x|=9
|-x|=-9
false, no negative absolute value
-|-x|=-2
|-x|=2
x=2 or -2
true, has solutions
the ones that have no solutions are
|x|=-15
-|x|=12
-|-x|=9
Answer:
(x+5) (x=3)
(X+5) (x+1)
Step-by-step explanation:
A removeable discontinuity is always found in the denominator of a rational function and is one that can be reduced away with an identical term in the numerator. It is still, however, a problem because it causes the denominator to equal 0 if filled in with the necessary value of x. In my function above, the terms (x + 5) in the numerator and denominator can cancel each other out, leaving a hole in your graph at -5 since x doesn't exist at -5, but the x + 1 doesn't have anything to cancel out with, so this will present as a vertical asymptote in your graph at x = -1, a nonremoveable discontinuity.
