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maxonik [38]
2 years ago
6

A college has thirteen instructors qualified to teach a special computer laboratory course which requires two instructors to be

present. How many different pairs of instructors could there be?
Mathematics
1 answer:
Kobotan [32]2 years ago
5 0

Answer:

156 different pairs will be there.

Step-by-step explanation:

As the order is  essential as we need different pairs therefore permutations will be used.

A permutation is any ordered subset of the objects r selected with regard to their order, from the set of  n distinct objects. It is given by nPr where n> r

Total number is 13 and required number is 2

n= 13 and r= 2

13 P2= 156 possible combinations.

A combination is any subset of the objects r selected without regard to their order, from the set of  n distinct objects. It is given by nCr where n> r

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The competition can be played in 7 different ways

Step-by-step explanation:

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<h3>Case - 2: X wins the fourth game:</h3>

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<h3>³⁻⁴Sub-sub-case - ii: Y wins the sixth game:</h3>

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<h3>Sub-case - b: Y wins the fifth game:</h3>

more games are required to decide the winner

<h3>⁵Sub-sub-case - i: Y wins the sixth game:</h3>

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<h3>⁶⁻⁷Sub-sub-case - ii: X wins the sixth game:</h3>

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