All categories

3 years ago

If I have a candy bar divided into 6 equal parts, and I eat 2 of the parts, what fraction of the candy bar did I eat?

Mathematics

2 answers:

Afina-wow [57]3 years ago

6 0

Answer:

2/6 or 1/3

Step-by-step explanation:

Nothing it is just basic mathematics

SVEN [57.7K]3 years ago

3 0

Eaten part=2
Total parts=6

Fraction form

$\\ \tt\rightarrowtail \dfrac{2}{6}$

$\\ \tt\rightarrowtail \dfrac{1}{3}$

You might be interested in

Solve the system of equations using any method. 2X – Y + Z = – 2, 6X + 3Y – 4Z = 8, – 3X + 2Y +3Z = – 6

krok68 [10]

Answer:

Z = - 2, Y = 0, X = 0

Step-by-step explanation:

2X – Y + Z = – 2

6X + 3Y – 4Z = 8

– 3X + 2Y +3Z = – 6

isolate "X" in the first equation

2X - Y + Z = - 2 => isolate "2X"

2X = - 2 - Z + Y => divide either side by 2

X = - 1 - Z/2 + Y/2

substitute this value of X in the second two equations (applying the substitution method here)

6(- 1 - Z/2 + Y/2) + 3Y - 4Z = 8,

6Y - 7Z - 6 = 8

- 3(- 1 - Z/2 + Y/2) + 2Y +3Z = - 6,

Y + 9Z + 6/2 = - 6

isolate Y in the second equation (6Y - 7Z - 6 = 8) and substitute in the third equation (Y + 9Z + 6/2 = - 6)

6Y - 7Z - 6 = 8 => isolate 6Y

6Y = 14 + 7Z => divide either side by 6

Y = 7Z + 14/6 => substitute in second equation

7Z + 14/6 + 9Z + 6/2 = - 6 => solve for Z

61Z + 50/12 = - 6, Z = - 2

substitute the value of Z into the equations "Y = 7Z + 14/6" and using the value of Y and Z, substitute into "X = - 1 - Z/2 + Y/2"

Y = (7(- 2) + 14)/6 = 0 / 6

= 0

X = - 1 - (- 2)/2 + 0/2 = - 1 - (-1) + 0

= - 1 + 1 + 0 = 0

6 0

3 years ago

HELP ASAP RN PLEASE!!<br><br> 200 people got an email 37 people clicked on it how do you get 18.5%

son4ous [18]

Answer:

37/200

Step-by-step explanation:

Event/Sample Space = .185 = 18.5%

7 0

3 years ago

Read 2 more answers

PLEASE ANSWER THE QUESTIONS ASAP

wariber [46]

Not sure about the first one, The second one is 1/9.

4 0

3 years ago

A car travels 2 1/3 miles in 3 1/2 minutes at a constant speed. Write an equation to represent the car travels in miles and minu

Korvikt [17]

Answer:

d = 0.666t , where d is in miles and t is in minutes.

d = 39.94h, where d is in miles and h is in hours.

Step-by-step explanation:

A car travels $2\frac{1}{3} = 2.33$ miles in $3\frac{1}{2} = 3.5$ minutes at a constant speed.

Let the relation between the distance (d) traveled by car in miles after traveling t minutes is d = kt ......... (1)

Now, putting d = 2.33 miles and t = 3.5 minutes in the above equation we get,

2.33 = 3.5k

⇒ k = 0.666 (Approx.)

So, the equation (1) becomes d = 0.666t. (Answer)

Let us assume that the relation between the distance (D) traveled by car in miles after traveling h hours is d = Kh ............ (2)

Now, putting D = 2.33 miles and T = 3.5/60 = 0.058 hours in the above equation, we get

2.33 = 0.058K

⇒ K = 39.94

So, the equation (2) we get, d = 39.94h (Answer)

3 0

3 years ago

Show that <br><br> 4(m + 7) + (m + 3)^2 = (m + 3)(m + 7) + 16

anygoal [31]

Step-by-step explanation:

$4(m+7)+(m+3)^2=(m+3)(m+7)+16\\\\L_S=4(m+7)+(m+3)^2\\\\\text{use the distributive property}:a(b+c)=ab+ac\\\text{and formula}:\ (a+b)^2=a^2+2ab+b^2\\\\L_S=(4)(m)+(4)(7)+m^2+2(m)(3)+3^2\\\\L_S=4m+28+m^2+6m+9\qquad\text{combine like terms}\\\\L_S=m^2+(4m+6m)+(28+9)\\\\L_S=m^2+10m+37$

$R_S=(m+3)(m+7)+16\\\\\text{use FOIL}:(a+b)(c+d)=ac+ad+bc+bd\\\\R_S=(m)(m)+(m)(7)+(3)(m)+(3)(7)+16\\\\R_S=m^2+7m+3m+21+16\qquad\text{combine like terms}\\\\R_S=m^2+(7m+3m)+(21+16)\\\\R_S=m^2+10m+37\\\\\boxed{L_S=R_S}$

4 0

3 years ago