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2 years ago

How many months is 82 weekdays ?

Mathematics

1 answer:

marin [14]2 years ago

3 0

3 months or 2 and some days

You can just take 82/30 = 2.73 for some approximation

or subtract each month length from it , witch give you March 23th if you start counting from January 1st

You might be interested in

Describe rotation in another way 83 degrees counter-clockwise

siniylev [52]

Answer:

<h2>277 degrees clockwise.</h2>

Step-by-step explanation:

This rotation could be express with its opposite. Just remember that a complete rotation is 360 degrees, so, if it's rotating 83° counter-clockwise, it'll be the same rotation if we say 277° clockwise, because that's the difference from the total 360°.

4 0

3 years ago

Find thr value of x. express your answer in simplest radical form<br><br>

Arte-miy333 [17]

11^2x11^2=x^2
121+121=x^2
242=x^2
Radical 242 = radical x^2
Full solved answer is 15.56

4 0

1 year ago

Rule: Add 3, subtract 2. first term 7

Kaylis [27]

By adding 3 then subtracting 2, you're pretty much just adding 1.

Starting from 7;

7, 8, 9, 10, 11, 12, etc.

I hope that helps!

6 0

2 years ago

Read 2 more answers

Three spherical balls with radius r are contained in a rectangular box. two of the balls are each touching 5 sides of the rectan

olganol [36]

Answer:

The volume of the space between the balls and the rectangular box is $4r^{3}(6 - \pi)$

Step-by-step explanation:

The attachment below shows the description of the rectangular bow and the three spherical balls.

From the description,

Two of the balls are each touching 5 sides of the rectangular box, say the 5 sides touched by one of the balls are sides 1,2,3,4, and 5; then the other ball will touch sides 2,3,4,5, and 6).
The middle ball also touches four sides of the rectangular box, These four sides touched by the middle ball will be sides 2,3,4, and 5.

This means the balls are tightly fitted into the rectangular box.

Each of the balls has a radius r

Hence, The volume of one of the balls is given by the volume of a sphere

$Volume of a sphere = \frac{4}{3} \pi r^{3} \\$

The volume occupied by one of the balls is $\frac{4}{3} \pi r^{3} \\$

∴ The volume occupied by the three spherical balls will be

3 × $\frac{4}{3} \pi r^{3} \\$

= $4\pi r^{3}$

The volume occupied by the three spherical balls $4\pi r^{3}$

For the rectangular box,

The volume of a rectangular box = $l w h$

Where $l\\$ is the length

$w$ is the width and

$h$ is the height

Since the balls are tightly packed,

The width of the rectangular box will be the diameter of the balls

diameter of the balls = 2r

∴ $w$ = 2r

The height of the rectangular box will also be the diameter of the balls

∴ $h$ = 2r

The length of the rectangular box will be 3 times the diameter of the balls

∴ $l$ = 3 × 2r = 6r

Hence,

The volume of a rectangular box = 6r × 2r × 2r

= 24r³

The volume of the space between the balls and the rectangular box is given by

Volume of the space between the balls and the rectangular box =

volume of the rectangular box - volume occupied by the three spherical balls

Volume of the space between the balls and the rectangular box= 24r³ - 4πr³

= 24r³ - 4πr³

= 4r³(6 - π)

5 0

2 years ago

What is the simplified form of x+3/x^2-x-12 times x-4/x^2-8x+16?

Alenkinab [10]

<span> $\frac{x+3}{x^2-x-12} * \frac{x-4}{x^2-8x+16} \\= \frac{x+3}{(x-4)(x+3)}* \frac{x-4}{(x-4)(x-4)} = \frac{1}{x-4}* \frac{1}{x-4} = \frac{1}{(x-4)^2}$ * </span><span>x-4/x^2-8x+16

Hope that helps
</span><span />

3 0

3 years ago