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blagie [28]
3 years ago
6

Biologists tagged 196 fish in a lake on January 1. On February​ 1, they returned and collected a random sample of 42 ​fish, 14 o

f which had been previously tagged. On the basis of this​ experiment, approximately how many fish does the lake​ have?
Mathematics
1 answer:
erastovalidia [21]3 years ago
3 0

Answer:

approximentley 588 fish live in the lake

Step-by-step explanation:

42 divided by 14 =3

196 multiplied by 3=588

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(SAT prep) In △ABC, AB = BC =20, DE ≈ 9.28. Approximate BD.
ankoles [38]

Answer: BD = 5.36 ≈ 5.4

Step-by-step explanation:

length of line AB = length of line BC = 20, line DE ≈ 9.28

Since the length of line AB and line BC are equal, it follows that the length of line BD and line EC are also equal. Therefore, to get the length of line BD will be the difference between the length of lines BC and DE; the result is then divided by 2. The result gives us the length of line BD or line EC because the length of lines BD and EC are equal [BD = EC]

Mathematically,

BD = \frac{BC - DE}{2} = \frac{20 - 9.28}{2} = \frac{10.72}{2}

BD = 5.36 ≈ 5.4

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3 years ago
What is the value of c
vredina [299]

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1

Step-by-step explanation:

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7 0
4 years ago
Determine the value of y.<br> (-7,y) (14,-5)<br><br> A. 1.25<br> B. 2.5<br> C. 5<br> D. 10
Gnesinka [82]
It should be D, if -7x-2 is 14, then -5x-2 will be 10.
7 0
4 years ago
8. The distribution for the time it takes a student to complete the fall class registration has mean of 94 minutes and standard
Alborosie

Answer:

Mean = 94

Standard deviation = 1.12

The sampling distribution of the sample mean is going to be normally distributed, beause the size of the samples are 80, which is larger than 30.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation, which is also called standard error s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 94, \sigma = 10

By the Central Limit Theorem

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Mean = 94

Standard deviation:

s = \frac{10}{\sqrt{80}} = 1.12

7 0
3 years ago
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3 years ago
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