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Aloiza [94]
3 years ago
5

Plz help

Mathematics
1 answer:
Snezhnost [94]3 years ago
5 0

Answer:

Step-by-step explanation:

tan~ \alpha =\frac{296}{135} \\\alpha =tan^{-1} (\frac{296}{135} )\approx 65.48 ^\circ\\

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15x+12=45+4x<br> whats x?
saul85 [17]

<span>15x+12=45+4x </span>⇒15x - 4x = 45 - 12 ⇒ 11x = 33 ⇒ x = 3


4 0
3 years ago
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PLZ PLZZZZ HELP ASAP!!!!! <br> Explain the error: 144x2 - 100 (12x + 10)(12x - 10) 2(6x + 5)(6x - 5)
iogann1982 [59]

9514 1404 393

Answer:

  a factor of 2 is shown, but 4 was factored out

Step-by-step explanation:

The difference of squares is factored as ...

  a² -b² = (a +b)(a -b)

Then the given difference of squares factors as ...

  144x² -100 = (12x)² -10² = (12x +10)(12x -10)

Each of these factors has a factor of 2 that can be factored out:

  = (2(6x +5))(2(6x -5))

  = (2·2)(6x +5)(6x -5)

  = 4(6x +5)(6x -5)

The first factor should be 4, not 2.

7 0
2 years ago
How many solutions to this equation?<br> 9x + 16 = 4x<br> A. 1<br> B. 0<br> C. infinitely many
Oksi-84 [34.3K]
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3 years ago
From a group of 8 volunteers, including Andrew and Karen, 4 people are to be selected at random to organize a charity event. Wha
Helga [31]

Answer:

The correct option is D. 2/7

Step-by-step explanation:

Consider the provided information.

There are 8 volunteers including Andrew and Karen, 4 people are to be selected at random to organize a charity event.

We need to determine the probability Andrew will be among the 4 volunteers selected and Karen will not.

We want to select Andrew and 3 others but not Karen in the group.

Thus, the number of ways to select 3 member out of 8-2=6

(We subtract 2 from 8 because Andrew is already selected and we don't want Karen to be selected, so subtract 2 from 8.)

The required probability is:

\dfrac{^6C_3}{^8C_4}=\dfrac{\frac{6!}{3!3!}}{\frac{8!}{4!4!}}\\\\\\\dfrac{^6C_3}{^8C_4}=\frac{20}{70}\\\\\\\dfrac{^6C_3}{^8C_4}=\dfrac{2}{7}

Hence, the correct option is D. 2/7

6 0
3 years ago
For items 5 - 7 consider the score distribution of 15
Vika [28.1K]
The median is 79. Hope this helps!
7 0
2 years ago
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