AD || BC
<span>• AB = CD </span>
<span>• ∠BAD = ∠CDA (a given condition ∵ ABCD is an isosceles trapezium) </span>
<span>The diagonals AC and BD create two ∆'s: ∆ABD, and ∆ACD </span>
<span>The two ∆'s are congruent (SAS). </span>
<span>(S): AB = CD </span>
<span>(A): ∠BAD = ∠CDA
</span><span>(S): AD = DA (common side) </span>
<span>
The corresponding sides of the two ∆'s, BD and AC, are also congruent. </span>
<span>(the two diagonals of the trapezium/trapezoid)
</span>
y2-y1 -8-24 -32 -1*2*2*2*4 16
M= --------- = ----------- = ------ = --------------- = ------
x2-x1 16-(-18) -2 -1*2 1
After a certain amount of time whoever asked the question gets to pick who gave them the brainliest answer, so its up to whoever asked the question whether they think you deserve it!
Answer:
x²+8x+16
Step-by-step explanation:
f(x) = (x+4)²
= (x+4)(x+4)
= x² + 4x + 4x + 16
= x² + 8x + 16
Answer:
The answer for this question is C, E and F .
Step-by-step explanation:
Given that the length is 3 times the width. So firstly, you have to find the expression of length :

Let width = w,


Next, the perimeter of rectangle is P = 2(length+width) so you have to substitute the expression into the formula :

Let length = 3w,
Let width = w,



