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Eddi Din [679]
3 years ago
13

The ability of a muscle to force against a resistance one time.

Physics
2 answers:
GuDViN [60]3 years ago
4 0

The answer to number 1 is A

Ksenya-84 [330]3 years ago
3 0
6 -B
7-D
8-D
9-D
11-A
12-A
13-B
14-D
15-A
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B. La velocidad de los electrones en los conductores metálicos es muy pequeña, del orden de algunos mm por segundo. ¿Cómo podría
Iteru [2.4K]

Answer:

electromagnetic wave. this energy is what lights the bulb.

Explanation:

When you close an electrical circuit, the electrons have a small drag speed, but the fluctuation of the electric field that is created originates by Lenz's law a magnetic field and the appearance of this magnetic field creates a fluctuating elective field, these two fields together forms a wave called an electromagnetic wave.

 This electromagnetic wave has a speed given by the relation

               v = √1 /ε μ

in a vacuum this speed is equal to the speed of light, which is worth 3 10⁸ m/s this very high value so the energy transported by this wave can travel the distance of 10 m in less than 10⁻⁷ s, This energy is what lights the bulb.

5 0
4 years ago
A moon of mass 1×10^20kg is in a circular orbit around a planet. The planet exerts a gravitational force of 2×10^21n on the moon
vagabundo [1.1K]

Hi there!

In this instance, the centripetal force experienced by the moon is equivalent to the gravitational force.

Thus:
\large\boxed{F_c = F_g}

Centripetal acceleration, according to Newton's Second Law:


\Sigma F = ma \\\\F_c = m * a_c\\\\a_c = \frac{F_c}{m}

Therefore:

a_c = \frac{F_g}{m_m} = \frac{2 * 10^{21}N}{1 * 10^{20}kg} = \boxed{20 N/kg}

6 0
2 years ago
What energy transformations occur in a tv remote?
Tatiana [17]
Pressing the button: Mechanical to electrical 
<span>Waste energy from this step: Mechanical to heat </span>
<span>Converting electrical signal to IR: electrical to electromagnetic (infrared rays) </span>
<span>Waste energy from this step: electrical to heat </span>
<span>Chemical energy from battery: chemical to electrical</span>
6 0
3 years ago
NVMMMMMMMMMMMMMMMMMMMM
sp2606 [1]
Huh??????????????????????????
8 0
3 years ago
Letting D D represent the maximum displacement, the extremes of the block's motion are at position A, where x = − D x=−D, and at
Ksju [112]

Answer:

The answer is at x = 0, which represents position B

Explanation:

The full question is:

"A block is attached to a horizontal spring and set in a

simple harmonic motion, as shown from above in the figure. When the spring is relaxed, the block is a position B, where the displacement x from the equilibrium position is 0. Letting D represent the maximum displacement, the extremes of the block's motion are at position A, where x= -D, and at position C, where x= D.

At what point in the motion is the speed of the block at its maximum?"

And you can see the figure on the attached file.

Simple Harmonic motion equations

We can start from the equation that describes the position that is

x(t)=D \sin\left(\omega t)

Here D stands for the amplitude which is the maximum displacement, and \omega is the angular velocity, thus we can find the derivative to find the velocity equation, so we get

v(t)=D \omega \cos (\omega t)

And we can find the derivative again to find the acceleration.

a(t) = -D\omega^2 \sin (\omega t)

Maximum speed

We reach the maximum speed when the acceleration equation is equal to 0,

a(t) =0\\-D\omega^2 \sin (\omega t)=0

Thus it happens when

\sin (\omega t)=0

So if we replace that on the position equation we get

x(t)=D \sin(\omega t) \\x(t)=D(0)\\x(t)=0

Thus the position where the speed of the block is at at its maximum is when it is going back to the origin, that is x = 0, so point b.

7 0
3 years ago
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