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Cerrena [4.2K]
3 years ago
8

Evaluate the expression. Write your answer in scientific notation. (9×10^−3)+(2.4×10^−5)÷0.0012

Mathematics
1 answer:
Feliz [49]3 years ago
7 0
This, you will have to use your calculator for, but I can still explain it.
First off, 9x10^-3 is equivalent to 0.009
Second: 2.4x10^-5 is equivalent to 0.000024
Parenthesis
Exponents
Multiple
Divide
Addition
Subtraction
PEMDAS is the order you go in always, if it's multiple or division, you do whichever one comes first, same with addition and subtracting, so left to right
FIRST: do 0.000024 / 0.0012 = 0.02
0.009 + 0.02 (answer above) = 0.29
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Answer:

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Step-by-step explanation:

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6 0
2 years ago
Simplify. Your answer should contain only positive exponents with no fractional exponents in the denominator.
mart [117]

Answer:

\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}.

Step-by-step explanation:

The given expression is  

\dfrac{3y^{\frac{1}{4}}}{4x^{-\frac{2}{3}}y^{\frac{3}{2}}\cdot 3y^{\frac{1}{2}}}

We need to simplify the expression such that answer should contain only positive exponents with no fractional exponents in the denominator.

Using properties of exponents, we get

\dfrac{3}{4\cdot 3}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{\frac{3}{2}+\frac{1}{2}}}    [\because a^ma^n=a^{m+n}]

\dfrac{1}{4}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{2}}

\dfrac{1}{4}\cdot \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{y^{2}}         [\because a^{-n}=\dfrac{1}{a^n}]

\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}

We can not simplify further because on further simplification we get negative exponents in numerator or fractional exponents in the denominator.

Therefore, the required expression is \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}.

5 0
4 years ago
Round to the nearest gram
earnstyle [38]

Alright, so after a half-life, half of the previous number would be left. So basically,

180 g ← 0 half lives

90 g ← 1 half life

45 g ← 2 half lives

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5 0
3 years ago
For which values of x is the expression x4 – 10x2 less than -9?
Julli [10]
x^4-10x^2\ \textless \ -9\\
x^4-10x^2+9\ \textless \ 0\\
x^4-x^2-9x^2+9\ \textless \ 0\\
x^2(x^2-1)-9(x^2-1)\ \textless \ 0\\
(x^2-9)(x^2-1)\ \textless \ 0\\
(x-3)(x+3)(x-1)(x+1)\ \textless \ 0\\
x\in(-3,-1)\cup(1,3)


4 0
3 years ago
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guajiro [1.7K]

Answer:

Step-by-step explanation:

C is 135'

A is 90'

B is 90'

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E is 45'

F is 135'

5 0
3 years ago
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