All categories

3 years ago

What is the distance between two points ( 3,-4)(-4,-4)

Mathematics

1 answer:

kirill [66]3 years ago

6 0

Answer:

To find the distance between two points, use the distance formula.

It will be the square root of (x2-x1)squared + (y2-y1)squared.

Use (3,-4) as x1, y1. Use (5,1) as x2, y2.

We get the square root of (5-3)squared + (1- -4)squared.

That gives us the square root of 2 squared + 5 squared.

Now we have the square root of 4 + 25, = the square root of 29.

That is the distance between the two points

Step-by-step explanation:

You might be interested in

37 hundreaths = ?tenths and ? hundreaths. HELP ME PLEASE AND SHOW ME HOW TO DO IT PLEASE.

Anuta_ua [19.1K]

0.37= 0.3 +0.07

3 tenth and 7 hundredths

6 0

3 years ago

Perform the indicated operation. (-7) • (-5) -12 35 12 -35

Flauer [41]

Hi,

Equation:

$- 7 \times (- 5)$

Multiplying two negatives equals a positive.

$( - ) \times ( - ) = ( + )$

Now equation looks like:

$7 \times 5 = 35$

Hope this helps.
r3t40

6 0

3 years ago

Read 2 more answers

HELP PLEASE FOR BRAINLIST!!!!!!!!!!!!

Sindrei [870]

Answer:

a(x) and d(x)

hope that helps, have a good day!

dont forget my brainliest.

Step-by-step explanation:

6 0

2 years ago

2) If the sales tax rate is 6.25% in Rio Rancho, how much would the sales tax be for a pair of shoes that cost

Marianna [84]

Answer:

Step-by-step explanation:

4 0

3 years ago

Triangle DEF has vertices D(0,0), E(7,0), and F(3,7).

Leni [432]

Answer:

(3, 1.7)

Step-by-step explanation:

The point at which the vertices of a triangle meet is known as the orthocenter of the triangle. The orthocenter passes through the vertex of the triangle and is perpendicular to the opposite sides.

Two lines are perpendicular if the product of their slopes is -1.

The slope of the line joining D(0,0), F(3,7) is:

$m_1=\frac{7-0}{3-0}=\frac{7}{3}$

The slope of the line perpendicular to the line joining D and F is -3/7. The orthocenter is perpendicular to the line joining D and F and passes through vertex E(7, 0). The equation is hence:

$y-y_1=m(x-x_1)\\\\y-0=-\frac{3}{7} (x-7)\\\\y=-\frac{3}{7}x+3 \ .\ .\ .\ (1)$

The slope of the line joining E(7,0), and F(3,7). is:

$m_1=\frac{7-0}{3-7}=-\frac{7}{4}$

The slope of the line perpendicular to the line joining E and F is 4/7. The orthocenter is perpendicular to the line joining E and F and passes through vertex D(0, 0). The equation is hence:

$y-y_1=m(x-x_1)\\\\y-0=\frac{4}{7} (x-0)\\\\y=\frac{4}{7} x\ .\ .\ .\ (2)$

The point of intersection of equation 1 and equation 2 is the orthocenter. Solving equation 1 and 2 simultaneously gives:

x = 3, y = 1.7

4 0

3 years ago