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3 years ago

What is the distance between two points ( 3,-4)(-4,-4)

Mathematics

1 answer:

kirill [66]3 years ago

6 0

Answer:

To find the distance between two points, use the distance formula.

It will be the square root of (x2-x1)squared + (y2-y1)squared.

Use (3,-4) as x1, y1. Use (5,1) as x2, y2.

We get the square root of (5-3)squared + (1- -4)squared.

That gives us the square root of 2 squared + 5 squared.

Now we have the square root of 4 + 25, = the square root of 29.

That is the distance between the two points

Step-by-step explanation:

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An employer has a staff of eighty actuaries, ten of whom are student actuaries. A student actuary is allowed a total of ten week

sergiy2304 [10]

Answer:

0.1111

Step-by-step explanation:

From the given information;

Number of staffs in the actuary = 80

Out of the 80, 10 are students.

i.e.

P(student actuary) = 10/80 = 0.125

number of weeks in a year = 52

off time per year = 10/52 = 0.1923

P(at work || student actuary) = (50 -10/52)

= 42/52

= 0.8077

P(non student actuary) = (80 -10)/80

= 70 / 80

= 0.875

For a non-student, they are only eligible to 4 weeks off in a year

i.e.

P(at work | non student) = (52-4)/52

= 48/52

= 0.9231

∴

P(at work) = P(student actuary) × P(at work || student actuary) + P(non student actuary) × P(at work || non studnet actuary)

P(at work) = (0.125 × 0.8077) + ( 0.875 × 0.9231)

P(at work) = 0.1009625 + 0.8077125

P(at work) = 0.90868

Finally, the P(he is a student) = (P(student actuary) × P(at work || student actuary) ) ÷ P(at work)

P(he is a student) = (0.125 × 0.8077) ÷ 0.90868

P(he is a student) = 0.1009625 ÷ 0.90868

P(he is a student) = 0.1111

5 0

3 years ago

Find values of  that satisfy the equation for 0º    360º and 0  θ  2 . Give answers in degrees and radians.

suter [353]

Answer:

$\theta = 30^\circ, 330^\circ$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

Step-by-step explanation:

Given [Missing from the question]

Equation:

$cos\theta = \frac{\sqrt 3}{2}$

Interval:

$0 \le \theta \le 360$

$0 \le \theta \le 2\pi$

Required

Determine the values of $\theta$

The given expression:

$cos\theta = \frac{\sqrt 3}{2}$

... shows that the value of $\theta$ is positive

The cosine of an angle has positive values in the first and the fourth quadrants.

So, we have:

$cos\theta = \frac{\sqrt 3}{2}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{\sqrt 3}{2})$

$\theta = 30$ --- In the first quadrant

In the fourth quadrant, the value is:

$\theta = 360 -30$

$\theta = 330$

So, the values of $\theta$ in degrees are:

$\theta = 30^\circ, 330^\circ$

Convert to radians (Multiply both angles by $\pi/180$ )

So, we have:

$\theta = \frac{30 * \pi}{180}, \frac{330 * \pi}{180}$

$\theta = \frac{\pi}{6}, \frac{33 * \pi}{18}$

$\theta = \frac{\pi}{6}, \frac{11 * \pi}{6}$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

8 0

3 years ago

2. What’s the answer to this question please

gladu [14]

I believe the answer is B because you distribute 4(x-8) to get 4x-32 and distribute 7(x-4) to get 7x-28

4 0

3 years ago

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Anyone want points or brainiest here is a question. What is 4-1! <br> :D

stira [4]

Answer:

it would 41 amiright?

7 0

3 years ago

Read 2 more answers

Help me please i really need it

Mariulka [41]

Answer:

can't tell it decreases and increases

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers