solution:
Consider the differential equation,
7ty + (1+t2)1/2y1 = 0
Rewrite the DE as,
(1+t2)1/2dy = - 7ty
dy/y = -7t/√1+t2 dt
in y = -7(1+t2) + c
y = ce-7(1+t2)
given,
y(0) = 1 => ce-7 = -1 => c = e7
ᴪ (t,y) = y -ce ᴪ(0,1)(1+t2)
Answer:
GoG = X⁴ + 4X² + 6
When squaring fractions, both the numerator and the denominator are squared:
12. (4/5)² = 16/25
13. (-5/12)² = 25/144
14. (13/6)² = 169/36
y+7=5/4(x-8)
Step-by-step explanation:
y-y1=m(x-x1)
y-(-7)=5/4(x-8)
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