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3 years ago

How do I add 1475.48+14.98?

Mathematics

1 answer:

Llana [10]3 years ago

4 0

Answer:1490

Step-by-step explanation:so while solving this question, you want to make sure the decimals are on top of each other. 8+8 is 16 so you write 6 and carry 1. 4+9 is 13 +1 =14, write 4 carry one across the decimals. 5+4 is 9 plus 1 equals 10 write zero carry 1. 7+1 is 8 plus 1 is 9 so you write that down and since 1 and 4 have no numbers under them, you write it down too giving you 1490.46

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3 years ago

Find the sum.<br>(w - 2.4) + (1 - 0.5w)

vodka [1.7K]

The sum of the given expression { (w - 2.4) + (1 - 0.5w) } is 0.5w - 1.4.

<h3>What is the sum of the given expression?</h3>

Given the expression in the question;

(w - 2.4) + (1 - 0.5w)

Remove the parenthesis

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3 years ago

Identify the terms,like terms,coefficient and constants

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3 years ago

You stand a known distance from the base of the tree, measure the angle of elevation the top of the tree to be 15â—¦ , and then

gogolik [260]

Answer:

The maximum possible error of in measurement of the angle is $d\theta_1 =(14.36p)^o$

Step-by-step explanation:

From the question we are told that

The angle of elevation is $\theta_1 = 15 ^o = \frac{\pi}{12}$

The height of the tree is h

The distance from the base is D

h is mathematically represented as

$h = D tan \theta$ Note : this evaluated using SOHCAHTOA i,e

$tan\theta = \frac{h}{D}$

Generally for small angles the series approximation of $tan \theta \ is$

$tan \theta = \theta + \frac{\theta ^3 }{3}$

So given that $\theta = 15 \ which \ is \ small$

$h = D (\theta + \frac{\theta^3}{3} )$

$dh = D (1 + \theta^2) d\theta$

=> $\frac{dh}{h} = \frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta$

Now from the question the relative error of height should be at most

$\pm p$ %

=> $\frac{dh}{h} = \pm p$

=> $\frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta = \pm p$

=> $d\theta = \pm \frac{\theta + \frac{\theta^3}{3} }{1+ \theta ^2} * \ p$

So for $\theta_1$

$d\theta_1 = \pm \frac{\theta_1 + \frac{\theta^3_1 }{3} }{1+ \theta_1 ^2} * \ p$

substituting values

$d [\frac{\pi}{12} ] = \pm \frac{[\frac{\pi}{12} ] + \frac{[\frac{\pi}{12} ]^3 }{3} }{1+ [\frac{\pi}{12} ] ^2} * \ p$

=> $d\theta_1 = 0.25 p$

Converting to degree

$d\theta_1 = (0.25* 57.29) p$

$d\theta_1 =(14.36p)^o$

4 0

3 years ago

How do I add 1475.48+14.98?​

How do I add 1475.48+14.98?