Answer:
The answer to your question is: third option is correct.
Step-by-step explanation:
The third option is correct
4(-2)⁻²(4)⁻³
Complete Question
Riya is applying to her garden. She applies it at a rate of 25, 000 cm³ of mulch for every m² of garden space. At what rate is Riya applying mulch in m³/m²
Answer:
0.25m³/m²
Step-by-step explanation:
We are told the Riya sprays mulch at 250,000cm³ per m²
To find the rate at which Riya is spaying the mulch in m³/m² we would have to convert 250,00cm³/m² to m³/m²
1 cm³ = 1 × 10^-6m³
250,000 cm³ = x m³
Cross Multiply
1 cm³ × xm³ = 250,000cm³ × 1 × 10^-6 m³
X
x m³ = 250,000cm³ × 1 × 10^-6 m³/1 cm³
= 0.25m³
Therefore, the rate at which Riya is spraying the mulch = 0.25m³/m²
The scatterplot shown includes the (blue) least-squares regression line, whose equation is y = .975 + .005x, where y is calories (in thousands) and x is years after 1960. Choose the correct statement.
Answer: In the given regression equation, the calories are in thousands. Therefore, the slope 0.005 (0.005 x 1000 =5 calories) means the consumption is increasing at a rate of 5 calories per year.
Hence the option a. Consumption is increasing at a rate of 5 calories per year. is correct
Answer:
8sin(x)cos³(x)
Step-by-step explanation:
sin(4x) +2 sin(2x) = 2sin(2x)*cos(2x) + 2sin(2x) = 2sin(2x)(cos2x + 1)=
= 2sin(2x)(cos²x - sin²x + cos²x + sin²x)=²2sin(2x)*(2cos²x)=
= 4*2sin(x)*cos(x)*cos²(x)= 8sin(x)cos³(x)
Answer: x=-5 and y=6
Step-by-step explanation: i hope i did it right tell if i didnt
