All categories

3 years ago

Which function is a quadratic function

Mathematics

1 answer:

olga nikolaevna [1]3 years ago

7 0

One-to-one and one-to-many relation is a function

You might be interested in

Function to inverse function f(x) =2x/3-17

ZanzabumX [31]

Answer:

Inverse function is $f^{-1}(x)=\frac{3}{2}x+\frac{51}{2}$ .

Step-by-step explanation:

Given function is $f\left(x\right)=\frac{2}{3}x-17$ .

Now we need to find the inverse of the given function.

Step 1: replace f(x) with y

$y=\frac{2}{3}x-17$

Step 2: switch x and y

$x=\frac{2}{3}y-17$

Step 3: solve for y

$x=\frac{2}{3}y-17$

$x+17=\frac{2}{3}y$

$\frac{3}{2}(x+17)=y$

$\frac{3}{2}x+\frac{51}{2}=y$

Hence required inverse function is $f^{-1}(x)=\frac{3}{2}x+\frac{51}{2}$ .

3 0

3 years ago

Equation 1:Ax+By=C Equation 2:Dx+Ey=F A, B, C, D, E, and F are non-zero real numbers. Which of the following could replace equat

Gnesinka [82]

A, B and E.

Adding and multiplying the terms allow them to keep working. However, you must make sure that each variable is changed each time. Not just one as in C and D.

7 0

3 years ago

Simplify:<br> 25x - 6X - 18x + 7

azamat

Answer:

x+7

Step-by-step explanation:

25x - 6x - 18x + 7

x + 7

6 0

2 years ago

Scientific Notation<br> 7.28 x 10^10

Vsevolod [243]

Answer:

72800000000

Step-by-step explanation:

7.28 * 10^10 = 72800000000

7 0

3 years ago

Read 2 more answers

A 10-foot ladder is leaning against a vertical wall. If the bottom of the ladder is being pulled away from the wall at the rate

Alex777 [14]

Answer:

The area is changing at 15.75 square feet per second.

Step-by-step explanation:

The triangle between the wall, the ground, and the ladder has the following dimensions:

H: is the length of the ladder (hypotenuse) = 10 ft

B: is the distance between the wall and the ladder (base) = 6 ft

L: the length of the wall (height of the triangle) =?

dB/dt = is the variation of the base of the triangle = 9 ft/s

First, we need to find the other side of the triangle:

$H^{2} = B^{2} + L^{2}$

$L = \sqrt{H^{2} - B^{2}} = \sqrt{(10)^{2} - B^{2}} = \sqrt{100 - B^{2}}$

Now, the area (A) of the triangle is:

$A = \frac{BL}{2}$

Hence, the rate of change of the area is given by:

$\frac{dA}{dt} = \frac{1}{2}[L*\frac{dB}{dt} + B\frac{dL}{dt}]$

$\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - B^{2}}*\frac{dB}{dt} + B\frac{d(\sqrt{100 - B^{2}})}{dt}]$

$\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - B^{2}}*\frac{dB}{dt} - \frac{B^{2}}{(\sqrt{100 - B^{2}})}*\frac{dB}{dt}]$

$\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - 6^{2}}*9 - \frac{6^{2}}{\sqrt{100 - 6^{2}}}*9]$

$\frac{dA}{dt} = 15.75 ft^{2}/s$

Therefore, the area is changing at 15.75 square feet per second.

I hope it helps you!

5 0

3 years ago