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ankoles [38]
3 years ago
9

Which function is a quadratic function

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
7 0
One-to-one and one-to-many relation is a function
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The forumal below is used to convert a temputure in degrees celsius, C, to a tempurturein degrees fahrenheit, F.
Vika [28.1K]

Answer:

59 F

Step-by-step explanation:

F=1.8C+32

Let C = 15

F = 1.8 (15) +32

Multiply 1.8 times 15

F = 27+32

F = 59

15 degrees C is 59 degrees F

5 0
2 years ago
13/10+2/100=?/100 do you guys know what it os
Mila [183]

Answer:

132

Step-by-step explanation:

13/10+2/100=?/100

Get a common denominator of 100 for the first term

13/10  * (10/10)  +2/100=?/100

130/100 + 2/100 = ?/100

132/100   = ? /100

4 0
3 years ago
Read 2 more answers
THANK YOU (PLEASE HELP) <3 C: TYSMMMM PLZZZ Write an equation of a parabola that is wider than the parent function, reflects
My name is Ann [436]

Answer:

y=-2x^2-4

Step-by-step explanation:

The parabola is wider than it's parent function, y = x^2. Therefore the coefficient, of x^2 (when you refer to quadratic equations it's a) should be greater than 1. Let's take 2.

y = 2x^2

Now it is reflected across the x-axis, so the equation turns to y = -2x^2. The vertex is shifted down 4. Note that it is shifted down, along the y-axis. This makes 'c' (again quadratic equations) -4.

Final Equation: y=-2x^2-4

3 0
2 years ago
"A rectangle has a height of 5 cm and its base is increasing at a rate" of 3/2 cm/min. When its area is 60 cm2, at what rate is
sukhopar [10]

Answer:

The diagonal is increasing at the rate of 119/104cm/min of the given rectangle.

Step-by-step explanation:

Dimensions of the rectangle

Height = 5cm

Rate of base = 3/2 cm/min

Area = 60cm^2

We know the area of a rectangle of given by = base* Height

b*h = 60

b*5 = 60

b = 12cm

Applying Pythagoras theorem while drawing a diagonal to the rectangle

  b^2 +h^2 =  D^2\\

 5^2 +12^2 = 13^2

so our diagonal will be 13cm  

Upon differentiating the area of the rectangle  we get

b*h = A=60cm^2

using  the chain rule of differentiation

h*db/dt + b*dh/dt  = 0

b*dh/dt = -h*db/dt

12*dh/dt = -5*3/2

dh/dt = -5/8 cm//min

so the height of the rectangle is decreasing at the rate of -5/8cm/min

now we have all the measurements we need

b = 12 , db/dt = 3/2cm/min

h = 5 , dh/dt = -5/8 cm/min

b^2 +h^2  = D^2

Upon differentiating we get

2b*db/dt + 2h*dh/dt = 2D*dD/dt

b*db/dt + h*dh/dt = D*dD/dt

12*3/2 + 5*(-5/8) = 13*dD/dt

18 -25/8 = 13*dD/dt

\frac{144-25}{8} = 13*dD/dt

dD/dt = \frac{119}{104} cm/min

Therefore the diagonal is increasing at the rate of 119/104cm/min of the given rectangle.

6 0
3 years ago
Solve the system of equations by substitution. What is the solution for x? (1 point)
Cerrena [4.2K]
                 2x + y = 1
          2x - 2x + y = 1 - 2x
                         y = 1 - 2x
                         y = -2x + 1
               4x + 2y = -1
    4x + 2(-2x + 1) = -1
4x + 2(-2x) + 2(1) = -1
          4x - 4x + 2 = -1
                         2 ≠ -1

The solution of the problem can't be a solution because they are both parallel lines, which means they have no solution.
8 0
3 years ago
Read 2 more answers
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