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3 years ago

Given: ΔPSQ, PS = SQ PΔPSQ = 50 SQ – PQ = 1 Find: Area of ΔPSQ

1 answer:

3 0

The first part is to find the length SQ which is equal to SP.
Use the sine rule.
SQ/sin 65 = (SQ - 1)/Sin50
(sin50)/(sin 65) = (SQ-1)/SQ
0.8452(SQ) = SQ-1
0.1547SQ = 1
SQ = 6.46
The formula to apply here is:
Area=1/2(SQ)(SQ)sin50
= 0.5 × 6.46 × 6.46 × sin50
= 15.984

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STALIN [3.7K]

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Step-by-step explanation:

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2 years ago

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Hello, I gotta turn it turn in this question today, help!!!!!!

Sladkaya [172]

Answer:

2 or -2

Step-by-step explanation:

If x² - 8x = -12

Step 1

We find x by solving

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3 years ago

write the equation of the line, with the given properties, in slope-intercept form. slope = -5, through (-4,4)

Daniel [21]

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Step-by-step explanation:

Since we are given the slope and the point, we can plug in the point to solve for y-intercept.

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3 years ago

Use the Newton-Raphson method to find the root of the equation f(x) = In(3x) + 5x2, using an initial guess of x = 0.5 and a stop

xxMikexx [17]

Answer with explanation:

The equation which we have to solve by Newton-Raphson Method is,

f(x)=log (3 x) +5 x²

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Initial Guess =0.5

Formula to find Iteration by Newton-Raphson method

$x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\\\\x_{1}=x_{0}-\frac{f(x_{0})}{f'(x_{0})}\\\\ x_{1}=0.5-\frac{\log(1.5)+1.25}{\frac{1}{1.5}+10 \times 0.5}\\\\x_{1}=0.5- \frac{0.1760+1.25}{0.67+5}\\\\x_{1}=0.5-\frac{1.426}{5.67}\\\\x_{1}=0.5-0.25149\\\\x_{1}=0.248$

$x_{2}=0.248-\frac{\log(0.744)+0.30752}{\frac{1}{0.744}+10 \times 0.248}\\\\x_{2}=0.248- \frac{-0.128+0.30752}{1.35+2.48}\\\\x_{2}=0.248-\frac{0.17952}{3.83}\\\\x_{2}=0.248-0.0468\\\\x_{2}=0.2012$

$x_{3}=0.2012-\frac{\log(0.6036)+0.2024072}{\frac{1}{0.6036}+10 \times 0.2012}\\\\x_{3}=0.2012- \frac{-0.2192+0.2025}{1.6567+2.012}\\\\x_{3}=0.2012-\frac{-0.0167}{3.6687}\\\\x_{3}=0.2012+0.0045\\\\x_{3}=0.2057$

$x_{4}=0.2057-\frac{\log(0.6171)+0.21156}{\frac{1}{0.6171}+10 \times 0.2057}\\\\x_{4}=0.2057- \frac{-0.2096+0.21156}{1.6204+2.057}\\\\x_{4}=0.2057-\frac{0.0019}{3.6774}\\\\x_{4}=0.2057-0.0005\\\\x_{4}=0.2052$