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4 years ago

Lamp, toaster, and a fan

Chemistry

1 answer:

Usimov [2.4K]4 years ago

5 0

Answer: Light, Thermal, Kinetic

Explanation:

The lamp converts the electric energy to light energy.

The toaster converts the electric energy to thermal energy.

The fan converts the electric energy to kinetic energy.

Good luck with your test!

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How many sodium ions in 2.00 mol of NaCl

tankabanditka [31]

1 mole of nacl has 1 mole of na ions
therefore 2 moles of nacl has 2 moles of na ions
Mole x L
= 2x6.02x10^23
=12.04 x 10^23

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3 years ago

Read 2 more answers

If the reactants are 10 kg what is the mass of the products

nlexa [21]

If the mass of both the reactants is 10kg then the mass of the products also equals 10kg.

It is due to the law of conservation of mass.

Mass can neither be created nor be destroyed.

7 0

3 years ago

MY NAME IS SPONGEBOB plz help LOL

liubo4ka [24]

Answer:a

Explanation:

6 0

3 years ago

Osmosis is the process responsible for carrying nutrients and water from groundwater supplies to the upper parts of trees. The o

liberstina [14]

Answer: Molar concentration of the tree sap have to be 0.783 M

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=iCRT$

where,

$\pi$ = osmotic pressure of the solution = 19.6 atm

i = Van't hoff factor = 1 (for non-electrolytes)

R = Gas constant = $0.0821\text{ L.atm }mol^{-1}K^{-1}$

T = temperature of the solution = $32^oC=[273+32]=305K$

Putting values in above equation, we get:

$19.6atm=1\times C\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 305K$

$C=0.783M$

Thus the molar concentration of the tree sap have to be 0.783 M to achieve this pressure on a day when the temperature is 32°C

4 0

3 years ago

What is the density of nitrogen gas if 0.186 g occupies a volume of 110 mL?

Anvisha [2.4K]

Answer:

$d=1.69\times 10^{-3}\ g/mL$

Explanation:

Given that,

Mass, m = 0.186 g

Volume occupies, V = 110 mL

We need to find the density of Nitrogen gas. The mass per unit volume is called density of an object. It is given by the formula as follows :

$d=\dfrac{m}{V}\\\\d=\dfrac{0.186\ g}{110\ mL}\\\\=1.69\times 10^{-3}\ g/mL$

So, the required density is $1.69\times 10^{-3}\ g/mL$ .

4 0

3 years ago