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larisa [96]
3 years ago
12

What is the molar mass of magnesium tartrate

Chemistry
2 answers:
BlackZzzverrR [31]3 years ago
4 0

Answer:

172.38

Explanation:

C_4H_4MgO_6\\C=12.01\\H=1.01\\Mg=24.30\\O=16.00\\\\4(12.01)+4(1.01)+24.30+6(16.00)\\48.04+4.04+24.30+96\\=172.38

C = 12.01

H=1.01

Mg=24.30

O =16.00

4(12.01)+4(1.01)+24.30+6(16.00)

48.04 +4.04+24.30+96

=172.38

Leya [2.2K]3 years ago
3 0

Answer:

172.385 g/mol

Explanation:

Magnesium Tartrate is C4H4MgO6

C - 12.01 g/mol

H - 1.01 g/mol

Mg - 24.305 g/mol

O - 16.00 g/mol

12.01(4) + 1.01(4) + 24.305 + 16(6) = 172.385 g/mol

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<u>Answer:</u> The concentration of SO_4^{2-} at equilibrium is 0.00608 M

<u>Explanation:</u>

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In the second dissociation, the ions will remain in equilibrium.

We are given:

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Equation for the second dissociation of sulfuric acid:

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<u>Initial:</u>            0.025            0.025      

<u>At eqllm:</u>      0.025-x          0.025+x        x

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Ka_2\text{ for }H_2SO_4=0.01

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