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Genrish500 [490]

3 years ago

14

A colony of bacteria starts with 50 organisms and quadruples each day. Write an exponential function, P(t), that represents the

population of the bacteria after t days.

1 answer:

Doss [256]3 years ago

5 0

P(t) = 50 x (4)^t ; 51200 bacteria

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Write an equation (-2, 10), (10, -14)

Brilliant_brown [7]

$\bf (\stackrel{x_1}{-2}~,~\stackrel{y_1}{10})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{-14}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-14}-\stackrel{y1}{10}}}{\underset{run} {\underset{x_2}{10}-\underset{x_1}{(-2)}}}\implies \cfrac{-24}{10+2}\implies \cfrac{-24}{12}\implies -2$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{10}=\stackrel{m}{-2}[x-\stackrel{x_1}{(-2)}]\implies y-10=-2(x+2) \\\\\\ y-10=-2x-4\implies y=-2x+6$

5 0

3 years ago

In an algebra class last year, students who earned grades of A spent 4.7 hours more on homework per week than students who earne

Neko [114]

<span>A = 4.7 + C
where A represents the students who got A's, and C is the number of hours that the C-grade students spent on homework per week</span>

8 0

3 years ago

(Will give brainiest)<br><br>5y - x = 10<br><br>4x - 4y = 1<br><br>12 = 6x + 3y

kow [346]

Is there any answer choices to what we are looking for?

7 0

3 years ago

A student builds a model of a race car. The scale is 1:15 in the scale model,the car is 8cm tall. How tall is the actual car?

ycow [4]

Answer: 120cm

Step-by-step explanation i took the test

5 0

2 years ago

Given that the quadratic equation has equal roots (k^2-1)x^2-2kx-3k-1=0

Alik [6]

Answer:

(See explanation for further details)

Step-by-step explanation:

The real expression is:

$(k^{2}-1)\cdot x{{2} - 2\cdot k \cdot x - 3\cdot k + 1 = 0$

The general equation for the second-order polynomial is:

$x = \frac{2\cdot k \pm \sqrt{4\cdot k^{2}-4\cdot (k^{2}-1)\cdot (-3\cdot k + 1)}}{k^{2}-1}$

This condition must be observed for the case of a quadratic equation with equal roots:

$4\cdot k^{2} - 4\cdot (k^{2}-1)\cdot (-3\cdot k + 1) = 0$

$k^{2} + (k^{2}-1)\cdot (3\cdot k + 1) = 0$

$k^{2} + 3\cdot k^{3} - 3\cdot k - k^{2}-1 = 0$

$3\cdot k^{3} - 3\cdot k - 1 = 0$

7 0

4 years ago