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Ivan
3 years ago
14

If x=-3 calculate the value of: 2x squared add x

Mathematics
1 answer:
eduard3 years ago
5 0
9 would be the right answer because -3 ^2 is 6 and 6 times 2 is 12 plus -3 is 9. so 9 is your final answer
You might be interested in
What is the volume, in cubic cm, of a cylinder with a height of 8cm and a base radius of 7cm, to the nearest tenths place?
FromTheMoon [43]

Answer:

Volume of the cylinder =  1230.88\,cm^3

Step-by-step explanation:

Height(h) of the cylinder = 8 cm

Radius(r) of the base= 7cm

Volume of a cylinder is:

                  = \pi \times r^2\times h

As,

   \pi =\dfrac{22}{7} = 3.14

Putting the values in the formula:

Volume is:

           =3.14\times(7\times7)\times8\\\\=3.14\times49\times8\\\\=3.14\times392\\\\=1230.88\,cm^3

The volume of the cylinder is :  1230.88\,cm^3

7 0
3 years ago
How do you solve his with working
AlexFokin [52]
Check the picture below.

a)

so the perimeter will include "part" of the circumference of the green circle, and it will include "part" of the red encircled section, plus the endpoints where the pathway ends.

the endpoints, are just 2 meters long, as you can see 2+15+2 is 19, or the radius of the "outer radius".

let's find the circumference of the green circle, and then subtract the arc of that sector that's not part of the perimeter.

and then let's get the circumference of the red encircled section, and also subtract the arc of that sector, and then we add the endpoints and that's the perimeter.

\bf \begin{array}{cllll}
\textit{circumference of a circle}\\\\ 
2\pi r
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{arc's length}\\\\
s=\cfrac{\theta r\pi }{180}
\end{array}\\\\
-------------------------------

\bf \stackrel{\stackrel{green~circle}{perimeter}}{2\pi(7.5) }~-~\stackrel{\stackrel{green~circle}{arc}}{\cfrac{(135)(7.5)\pi }{180}}~+
\stackrel{\stackrel{red~section}{perimeter}}{2\pi(9.5) }~-~\stackrel{\stackrel{red~section}{arc}}{\cfrac{(135)(9.5)\pi }{180}}+\stackrel{endpoints}{2+2}
\\\\\\
15\pi -\cfrac{45\pi }{8}+19\pi -\cfrac{57\pi }{8}+4\implies \cfrac{85\pi }{4}+4\quad \approx \quad 70.7588438888



b)

we do about the same here as well, we get the full area of the red encircled area, and then subtract the sector with 135°, and then subtract the sector of the green circle that is 360° - 135°, or 225°, the part that wasn't included in the previous subtraction.


\bf \begin{array}{cllll}
\textit{area of a circle}\\\\ 
\pi r^2
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{area of a sector of a circle}\\\\
s=\cfrac{\theta r^2\pi }{360}
\end{array}\\\\
-------------------------------

\bf \stackrel{\stackrel{red~section}{area}}{\pi(9.5^2) }~-~\stackrel{\stackrel{red~section}{sector}}{\cfrac{(135)(9.5^2)\pi }{360}}-\stackrel{\stackrel{green~circle}{sector}}{\cfrac{(225)(7.5^2)\pi }{360}}
\\\\\\
90.25\pi -\cfrac{1083\pi }{32}-\cfrac{1125\pi }{32}\implies \cfrac{85\pi }{4}\quad \approx\quad 66.75884

7 0
3 years ago
What is the simple interest of a note that has a face value of $12,000, a rate of 8%, and a term of 1 year?
Tju [1.3M]

Solution:

Given:

\begin{gathered} P=\text{ \$}12,000 \\ R=8\text{ \%} \\ T=1year \end{gathered}

Using the simple interest formula,

\begin{gathered} I=\frac{PTR}{100} \\ I=\frac{12000\times1\times8}{100} \\ I=\text{ \$}960 \end{gathered}

Therefore, the simple interest is $960.

8 0
2 years ago
What is the surface area of this right rectangular prism glass slab with dimensions of 20 inches by 3 inches by 12 inches?
Art [367]

Answer:

C. 672

Step-by-step explanation:

7 0
3 years ago
Mr. Monasterio ran to the store for burritos at 4 miles per hour. On the way back, he increased his speed to 6 miles per hour. I
sveticcg [70]

Answer:

It took 1.2 hours to get to the store

Step-by-step explanation:

Let the time taken to reach the store be t₁

Let the time taken to come back be t₂

Let the speed to and from store = s₁ and s₂ respectively

let the distance to the store = d

To the store:

speed = \frac{distance}{time} \\s = \frac{d}{t_1} \\t_1 = \frac{d}{s_1}\\t_1 =\frac{d}{4} - - - - - (1)

Back from the store:

s_2 = \frac{d}{t_2} \\t_2 = \frac{d}{s_2}\\where:\\s_2 = 6\ miles\ per\ hour\\t_2 = \frac{d}{6} - - - - - - (2)

We are told that total time (t₁ + t₂) = 2 hours

t₁ + t₂ = eqn (1) + eqn (2)

\frac{d}{4} + \frac{d}{6} = 2\\Multiplying\ through\ by\ 12:\\3d\ +\ 2d\ =\ 24\\5d = 24\\d = \frac{24}{5} \\d = 4.8\ miles

∴ length of trip to the store = t₁

from eqn (1)

t_1 = \frac{d}{4} \\t_1 = \frac{4.8}{4} \\t_1 = 1.2\ hours

7 0
3 years ago
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