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Levart [38]
3 years ago
8

R+r+2r-r+4r combine like terms and solve

Mathematics
1 answer:
goldenfox [79]3 years ago
6 0

R+r+2r-r+4r

R + r + 2R + 4r = R+7r

R+7r - -r =

R+6r

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Find the value for the given variables. Give the variables in simplest radical form. (square root form)
Trava [24]

Answer:

x = 16, y = 16\sqrt{3}

Step-by-step explanation:

Because that triangle has a 60 degree angle, it is an semi-equilateral triangle.

In a semi-equilateral triangle:

The small side, in this case, x = hypotenuse / 2

The hypotenuse is 32, divide it by 2, and it's 16.

x = 16

In a semi-equilateral triangle:

The large side, in this case, y = small side \sqrt{3}

We already stated that the small side is 16, so the large one is just 16\sqrt{3}

Easy!

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What are 2 real life slope problems?
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Solve for x:<br> 3/ X - 4 = 6/ X+1
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3 years ago
And wins a metal in the shape of a circle for finishing a marathon which statements about the metals are true use 3.14 for pi. S
PilotLPTM [1.2K]

Answer:

The true statements are:

C. If the metal has a radius of 2.5 inches then it has an area of 19.625 in.²

D. If the metal has a diameter of 3 inches and it has a circumference of 9.42 inches.

E. If the metal has a circumference of four pi inches then it has an area of four pi square inches

Step-by-step explanation:

Let us revise the rule of circumference and area of a circle

  • The formula of the circumference of a circle is <em>C = π d</em>, where d is the diameter of the circle OR <em>C = 2πr</em>, where r is the radius of the circle
  • The formula of the area of a circle is <em>A = πr²</em>
  • The radius of a circle is equal to half its diameter

A.

∵ The metal has a circumference of 7π inches

∵ C = 2πr

- Equate πd by 7π

∴ πd = 7π

- Divide both sides by π

∴ d = 7 inches not 3.5 inches

∴ A is not true

B.

∵ The metal has a circumference of 3π inches

∵ C = 2πr

- Equate 2πr by 3π

∴ 2πr = 3π

- Divide both sides by π

∴ 2r = 3

- Divide both sides by 2

∴ r = 1.5 inches

∵ A = πr²

∴ A = π(1.5)²

∴ A = 2.25π inches² not 9π inches²

∴ B is not true

C.

∵ The metal has a radius of 2.5 inches

∴ r = 2.5

∵ A = πr²

∵ π = 3.14

∴ A = 3.14(2.5)²

∴ A = 19.625 inches²

∴ If the metal has a radius of 2.5 inches, then its area is 19.625 in.²

∴ C is true

D.

∵ The metal has a diameter of 3 inches

∴ d = 3

∵ C = πd

∵ π = 3.14

∴ C = 3.14(3)

∴ C = 9.42 inches

∴ If the metal has a diameter of 3 inches, then its circumference

  is 9.42 inches

∴ D is true

E.

∵ The metal has a circumference of 4π inches

∵ C = 2πr

- Equate 2πr by 4π

∴ 2πr = 4π

- Divide both sides by 2π

∴ r = 2

- Now you can find the area

∵ A = πr²

∴ A = π(2)²

∴ A = 4π

∴ If the metal has a circumference of 4π inches, then its area

   is 4π  inches²

∴ E is true

The true statements are:

C. If the metal has a radius of 2.5 inches then it has an area of 19.625 in.²

D. If the metal has a diameter of 3 inches and it has a circumference of 9.42 inches.

E. If the metal has a circumference of four pi inches then it has an area of four pi square inches

8 0
3 years ago
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