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3 years ago

PLEASEEEEE HELP!!!!!!!!

Physics

1 answer:

Umnica [9.8K]3 years ago

6 0

Gamma waves have the highest frequencies and shortest wavelengths

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Explanation:

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3 years ago

How do electromagnetic and mechanical waves compare?

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3 years ago

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How does quantum theory explain the emission spectra of atoms?

ankoles [38]

The correct answer is B.

Let us think of the classical theory first. In the classical theory, light is a wave that gives energy. This energy gradually helps the electron jump to a higher energy level.
In quantum theory, this is wrong; an electron cannot absorb a small amout of energy because there is not close enough state to jump to with that energy; only very specific amounts of energy lead to a change in orbital levels/ absorbance of energy. Also, each pair of energy levels has a specific energy difference that is needed from an electron so that it can move.
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3 years ago

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How much force is required to produce a torque of 100 Nm if the force is applied at an angle of 40 at a distance of 25 cm from t

Fudgin [204]

Answer:

Force, F = 622.28 N

Explanation:

It is given that,

Torque, $\tau=100\ N-m$

Angle between force and displacement, $\theta=40^{\circ}$

Distance, d = 25 cm = 0.25 m

We need to find the force required to produce the torque. Torque produced by an object is given by :

$\tau=Fd\sin\theta$

F is force required to produce torque

$F=\dfrac{\tau}{d\sin\theta}\\\\F=\dfrac{100}{0.25\times \sin(40)}\\\\F=622.28\ N$

So, applied force is 622.28 N.

7 0

3 years ago

the record for a ski jump is 180 m set in 1989. Assume the jumper comes off the end of the ski jump horizontally and falls 90 m

Mashutka [201]

Let's write the equations of motion on both x- (horizontal) and y- (vertical) axis. On the x-axis, it's a uniform motion with constant velocity vx. On the y-axis, it is a uniformly accelerated motion with initial height h=90 m and acceleration of $g=9.81 m/s^2$ pointing down (so with a negative sign):
$S_x(t)=v_x t$
$S_y(t)=h- \frac{1}{2} gt^2$

First, let's find the time at which the jumper reaches the ground. This happens when Sy(t)=0:
$0=h- \frac{1}{2} g t^2$
and so
$t= \sqrt{ \frac{2h}{g} }= \sqrt{ \frac{2\cdot 90m}{9.81 m/s^2} }=4.28 s$

Then, we can find the horizontal speed. In fact, we know that at the time t=4.28 s, when the jumper reached the ground, he covered exactly 180 m, so Sx=180 m. Using this into the law of motion in x, we find
$v_x= \frac{S_x}{t} = \frac{180 m}{4.28 s} =42 m/s$

8 0

3 years ago