A dragster gets to a speed of 112 m/s over a distance of 300 m from the rest, then the acceleration will be 20.9 m/s².
<h3>What is Acceleration?</h3>
The rate of change in an object's velocity with respect to time is known as acceleration in mechanics. The vector quantity of accelerations. The direction of the net force that is acting on an object determines its acceleration.
Since acceleration has both a magnitude and a direction, it is a vector quantity. Velocity is a vector quantity as well. The definition of acceleration is the change in velocity vector over a time interval divided by the time interval.
According to the question, the given values are :
Final velocity, v = 112 m/s.
Initial velocity, u = 0 m/s
Distance, s = 300 m.
Use the equation of motion,
v² - u² = 2as
112 ² - 0 = 2 (a)(300)
a = 12544/600
a = 20.9 m/s².
Hence, the acceleration of the dragster will be 20.9 m/s².
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Answer:
160 m/s
Explanation:
The Ferrari is moving by uniformly accelerated motion, with constant acceleration of a = 50 m/s^2, and initial velocity u = 10 m/s. The velocity at time t of the car is given by
where
u = 10 m/s
a = 50 m/s^2
If we substitute t = 3 s into the equation, we can find the velocity of the car after 3 seconds:
Answer:
2795.3 J
Explanation:
distance, d = 28 feet = 8.53 m
Force, F = 80 lb = 356 N
Angle, θ = 23°
Work = F x d x cos θ
W = 356 x 8.53 x cos 23
W = 2795.3 J
Thus, the work done is 2795.3 J.
Answer:
16. 68.18 Km/h
17. 3 miles.
Explanation:
16. Determination of the speed
Distance travelled = 150 Km
Time = 2.2 hours
Speed =?
Speed is simply defined as the distance travelled with time. Mathematically, it is expressed as:
Speed = Distance / time
With the above formula, we can obtain the speed as follow:
Distance travelled = 150 Km
Time = 2.2 hours
Speed =?
Speed = Distance /time
Speed = 150 / 2.2
Speed = 68.18 Km/h
17. Determination of the distance.
Speed = 3 mph
Time = 1 hour
Distance =?
Speed = Distance /time
3 = distance / 1
Distance = 3 miles
