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4 years ago

What is the difference between work and power

Physics

2 answers:

Luden [163]4 years ago

7 0

Power is the rate in which work is being done

dimulka [17.4K]4 years ago

6 0

Hello!

Explanation:

↓↓↓↓↓↓↓↓↓↓↓

Work is done by a force on an object. It can causes an object to move. It requires motion (no motion = no work). Object moving in the same direction as the force = work. Object moving in a different direction than the force= no work. Work is equal to the force exerted on an object times the distance it moves. The metric unit for work is the joule (J). 1 joule= 1 newton-meter. The amount of work done is not affected by the time it takes to do the work. Power is the rate which work is done. Power equals work divided by time. The metric unit for power is the watt (W). 1 watt= 1 joule per second.

Work formula:

↓↓↓↓↓↓↓↓↓↓↓↓

$W=Fd$

Power formula:

↓↓↓↓↓↓↓↓↓↓↓↓

$P=\frac{W}{t}$

Hope this helps!

Thank you for posting your question at here on brainly.

-Charlie

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Nuclear chain reactions within power plants do NOT produce bomb-like explosions primarily because the ________.

Gelneren [198K]

Answer: D. Density of uranium within nuclear fuel rods is insufficient to become explosive

Explanation: Nuclear power plants use the same fuel as nuclear bombs, i.e. radioactive Uranium-235 isotope. However, in a nuclear power plant, the energy is released more slowly unlike in a nuclear bomb. The energy released is through nuclear fission, and radioactive decay occurs at the same rate as in nuclear bombs. therefore, option A, B and C are incorrect.

The primary reason why nuclear chain reactions within power plants do NOT produce bomb-like explosions is because the uranium fuel rods used in electricity generation is not sufficiently enriched in Uranium-235 to produce a nuclear detonation. This is the same idea in option D which is the correct option.

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3 years ago

You find it takes 200 N of horizontal force tomove an unloaded pickup truck along a level road at a speed of2.4 m/s. You then lo

IgorC [24]

ANSWER:

F(h)= 230 N is the horizontal force you will need to move the pickup along the same road at the same speed.

STEP-BY-STEP EXPLANATION:

F(h) is Horizontal Force = 200 N

V is Speed = 2.4 m/s

The total weight increase by 42%

coefficient of rolling friction decrease by 19%

Since the velocity is constant so acceleration is zero; a=0

Now the horizontal force required to move the pickup is equal to the frictional force.

F(h) = F(f)

F(h) = mg* u

m is mass

g is gravitational acceleration = 9.8 m/s^2

200 = mg*u

Since weight increases by 42% and friction coefficient decreases by 19%

New weight = 1+0.42 = 1.42 = (1.42*m*g)

New friction coefficient = μ = 1 - 0.19 = 0.81 = 0.81 u

F(h) = (0.81μ) (1.42 m g)

= (0.81) (1.42) (μ m g)

= (0.81) (1.42) (200)

= 230 N

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3 years ago

At an instant when a soccer ball is in contact with the foot of the player kicking it, the horizontal or x component of the ball

dedylja [7]

Answer:

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Explanation:

We have given x component of acceleration $a_x=760m/sec^2$

And vertical component of acceleration $a_y=770m/sec^2$

Mass of the ball m = 0.40 kg

So net acceleration $a=\sqrt{a_x^2+a_y^2}=\sqrt{760^2+770^2}=1081.896m/sec^2$

Now according to second law of motion

Force = mass × acceleration

So F = 0.40×1081.896 = 432.758 N

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KatRina [158]

Answer:

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Answer:

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