The proton (positive charge) shall be closer to the charge with the lower magnitude which is at the orgin.
The proton also shall be out of the interval between the two charges so that the pull of one charge cancels with the push of the other.
The region at which those conditions happen is to the left of the origin.
In that case the forces over the proton shall be:
k* (2.4 nC) * p / (x^2) - k*(4.8 nC) * p /( 1.3 + x)^2 = 0
where p is the charge of the proton.
You can simplify k and p:
2.4 / x^2 - 4.8 / (1.3 + x)^2 = 0
You can also simplify by 2.4
1/ x^2 - 2 / (1.3 + x)^2 = 0
(1.3+x)^2 - 2x^2 = 0
1.69 + 2.6x + x^2 - 2x^2 = 0
1.69 + 2.6x - x^2 = 0
x^2 -2.6x - 1.69 =0
Solve using the quadratic formula: x = 3.14 (use only the positive value)
That is the proton shall be place 3.14 units to the left of the origin (positive charge)
I can't write an essay for you but i will give you some examples.
Many things today is dependent of electricity.
Phones, tvs gone.
No way to spread media.
satellites in space would fall on to earth causing damage and wreck.
Chaos would erupt.
Imagine what would happen to food and farms around the world.
Answer:
height of oil=60*13600/850=960 cm oil
Answer:
312 kJ
Explanation:
The thermal energy contained in a cubic meter of air at room temperature (20 C) and one atmosphere (101 kPa) would be.
H = Cv * T + p * V
Being
Cv: specific heat of air at constant volme (0.72 kJ/(kg*K))
T: temperature in absolute scale (20C is 293 K)
Then:
H = 0.72 * 293 + 101 * 1 = 312 kJ
The only way to extract thermal energy from a body and turn it into useful work (such as charging a phone) is to exchange heat with it and a another colder body. So, with just the air at room temperature it is impossible to extract its heat energy.