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tino4ka555 [31]

3 years ago

6

Select all the correct answers.

2 answers:

geniusboy [140]3 years ago

7 0

<span>Rectangular Prism Volume = length × width × height
</span>
So 4 of those could make the prism:
<span>2 units, 3 units, 6 units
36 units, 1 unit, 1 unit
9 units, 2 units, 2 units
12 units, 3 units, 1 unit
</span>

<span />

kodGreya [7K]3 years ago

4 0

Answer:

You're answer would be B , D E

Step-by-step explanation:

Sorry if it's wrong, I did a test and these answers were right

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Find the interquartile range of the data.

SCORPION-xisa [38]

The correct answer is D.14.
The interquartile range is the difference between the Upper Quartile and the Lower Quartile of a data set.

By arranging the numbers in the stem and leaf plot from lowest to highest value, you get an even set of data (31,33,35,41,43,46,48,49,49,50). By dividing the set into two, you get a lower half of your data (31,33,35,41,43) and an upper half (46,48,49,49,50). The lower quartile is the median or the midpoint of the lower half of your data while upper quartile is for the upper half. The lower quartiles is 35 and upper quartile is 49. The difference between the two is 14.

8 0

4 years ago

Which number line shows the solution of 5x-25<-15?<br> givning brainliest

Nata [24]

Answer:

x < 2

Step-by-step explanation:

5x-25<-15

Add 25 to each side

5x-25+25<-15+25

5x < 10

Divide by 5

5x/5 < 10/5

x < 2

Open circle at 2 line to left

6 0

2 years ago

In the freshman class, 62% of the students take math, 49% take science, and 38% take both science and math. what percentage take

antoniya [11.8K]

we are given

62% of the students take math

so,

$n(M)=62$

49% take science

$n(S)=49$

38% take both science and math

n(M∩S)=38

now, we can use union formula

n(M∪S)=n(M)+n(S) -n(M∩S)

now, we can plug values

and we get

n(M∪S)=62+49 -38

n(M∪S)=73

so,

the percentage takes at least one science or math course is 73%..........Answer

8 0

3 years ago

Read 2 more answers

What is the arc measure, in degrees, of major arc \stackrel{\large{\frown}}{ADC} ADC ⌢ A, D, C, start superscript, \frown, end s

Mrrafil [7]

Answer:

$\stackrel{\large{\frown}}{ADC} = 186^{\circ}$

Step-by-step explanation:

Given

See attachment

Required

Determine the measure of $\stackrel{\large{\frown}}{ADC}$

$The\ sum\ of\ angles\ in\ a\ circle\ is$ $360^{\circ}$ .

So, we have:

$\stackrel{\large{\frown}}{ADC} + \stackrel{\large{\frown}}{APB} + \stackrel{\large{\frown}}{BPC} = 360^{\circ}$

Where:

$\stackrel{\large{\frown}}{APB} = 70^{\circ}$

$\stackrel{\large{\frown}}{BPC} = 104^{\circ}$

Substitute these values in the above equation.

$\stackrel{\large{\frown}}{ADC} + 70^{\circ} +104^{\circ} = 360^{\circ}$

$\stackrel{\large{\frown}}{ADC} + 174^{\circ} = 360^{\circ}$

Collect Like Terms:

$\stackrel{\large{\frown}}{ADC} = 360^{\circ} - 174^{\circ}$

$\stackrel{\large{\frown}}{ADC} = 186^{\circ}$

7 0

3 years ago

Read 2 more answers

Help please! worth a lot of points! Screenshot included

vlada-n [284]

Answer:

x=44444444444444444444444444444444

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers