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lutik1710 [3]
3 years ago
10

A regular hexagon has an apothem of 14.7 inches and a perimeter of 101.8 inches. What is the area of the hexagon?

Mathematics
2 answers:
Neporo4naja [7]3 years ago
7 0

<u>Answer</u>

748.23 in²


<u>Explanation</u>

Apothem a line from the centre of a regular polygon at right angles to any of its sides. This can be said to be the height of the triangle in a polygon.

The base of the  hexagon = 101.8 ÷ 6

                                            = 19.96666..

                                            = 19.9667 inches

Area of the  hexagon = 1/2 × height × base length × 6

                                     = 1/2 × 14.7 × 19.9667 × 6

                                      = 748.23 in²

Mariana [72]3 years ago
7 0

Answer:

748.23

Step-by-step explanation:

its good

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  (-239.4, 657.8) km/h

Step-by-step explanation:

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Two more than four times a number is the same as 6 more than twice the number find the number ​
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The number is 2. :)

Step-by-step explanation:

4x + 2 = 2x + 6

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7 0
3 years ago
A plane flying horizontally at an altitude of 2 mi and a speed of 540 mi/h passes directly over a radar station. Find the rate a
Rasek [7]

Answer:

The plane's distance from the radar station will increase about 8 miles per minute when it is 5 miles away from it.

Step-by-step explanation:

When the plane passes over the radar station, the current distance is the altitude h = 2. Then it moves b horizontally so that the distance to the station is 5. We can form a rectangle triangle using b, h and the hypotenuse 5. Therefore, b should satisfy

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b² = 25-4 = 21, thus

b = √21.

Since it moved √21 mi, then the time passed is √21/540 = 0.008466 hours, which is 0.51 minutes. Note that in 1 minute, the plane makes 540/60 = 9 miles.

The distance between the plane and the radar station after x minutes from the moment that the plane passes over it is given by the function

f(x) = \sqrt{((9x)^2 + 2^2)} = \sqrt{(81x^2+4)}

We have to compute the derivate of f in x = 0.51. The derivate of f is given by

f'(x) = \frac{162x}{2\sqrt{81x^2+4}}

also,

f'(0.51) = \frac{162*0.51}{2\sqrt{81*0.51^2+4}} = 8.2486

The plane's distance from the station will increase about 8 miles per minute.

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If angle vuw = 4x+6 and wut = 6x+10 what is the measure of wut
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C, 38°

Step-by-step explanation:

ray UW is the angle bisector of ∠VUT

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So, the measure of m∠WUT is: 6x - 10 = 6 . 8 - 10 = 48 - 10 = 38°

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