Answer:
(-239.4, 657.8) km/h
Step-by-step explanation:
Measured CCW from the +x axis, the angle at which the airplane is traveling is 110°. Then the (x, y) components of the velocity vector are ...
(700 km/h)(cos(110°), sin(110°)) ≈ (-239.4, 657.8) km/h
Answer:
The number is 2. :)
Step-by-step explanation:
4x + 2 = 2x + 6
-2 -2
4x = 2x + 4
-2x -2x
2x = 4
/2 /2
x = 2
Answer:
The plane's distance from the radar station will increase about 8 miles per minute when it is 5 miles away from it.
Step-by-step explanation:
When the plane passes over the radar station, the current distance is the altitude h = 2. Then it moves b horizontally so that the distance to the station is 5. We can form a rectangle triangle using b, h and the hypotenuse 5. Therefore, b should satisfy
h²+b² = 5², since h = 2, h² = 4, as a result
b² = 25-4 = 21, thus
b = √21.
Since it moved √21 mi, then the time passed is √21/540 = 0.008466 hours, which is 0.51 minutes. Note that in 1 minute, the plane makes 540/60 = 9 miles.
The distance between the plane and the radar station after x minutes from the moment that the plane passes over it is given by the function

We have to compute the derivate of f in x = 0.51. The derivate of f is given by

also,

The plane's distance from the station will increase about 8 miles per minute.
Length of the model = 11.6 inch
Answer:
C, 38°
Step-by-step explanation:
ray UW is the angle bisector of ∠VUT
--> m∠VUW = m∠WUT = 1/2 m∠VUT
<=> 4x + 6 = 6x - 10
<=> 6 + 10 = 6x - 4x
<=> 2x = 16
<=> x = 8
So, the measure of m∠WUT is: 6x - 10 = 6 . 8 - 10 = 48 - 10 = 38°