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scZoUnD [109]
3 years ago
11

The product of five and a number plus 10 is at least thirty.

Mathematics
1 answer:
Vlad [161]3 years ago
3 0
5+10+x is greater than or equal to 30 ( use the greater of equal to sign)
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What is m&lt;KPN?<br>What is m&lt;MPL?
Zielflug [23.3K]
X - 3 + 2x = 90
3x - 3 = 90
3x = 90 + 3
3x = 93
x = 93/3
x = 31

< KPN = 2x......2(31) = 62
< MPL = x - 3....31 - 3 = 28 
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4 years ago
The following equation is a linear equation that has a slope of 3 and a y-intercept of positive 2:
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The y intercept in the equation is -2. What is your question?
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If the only common factor of two numbers is 1, then to find the LCM, simply multiply the numbers together. True or false.
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The 90% confidence interval for the mean one week amusing time in new york city is 5.22 less than mean less than 5.98 minutes co
jasenka [17]

The 95% confidence interval based on the same data is 5.15 < μ < 6.05

Because it has a longer interval, the 95 percent confidence interval offers more details.

<h3>What is a confidence interval?</h3>

The likelihood that a parameter will fall between two values near the mean is shown by a confidence interval.

Confidence intervals quantify how certain or uncertain a sampling technique is.

Confidence intervals are used by statisticians to gauge the degree of uncertainty in a sample variable.

The 90% confidence interval is given by:

Mean - 1.645(S.D./\sqrt{n}) < μ < Mean + 1.645(S.D./\sqrt{n})

2μ = 5.22 + 5.98 = 11.2

μ = 11.2 / 2 = 5.6

Thus,

5.6 - 5.22 = 1.645(S.D./\sqrt{n}) = 0.38

S.D./\sqrt{n} = 0.38 / 1.645 = 0.231

The 95% confidence interval is given by:

Mean - 1.96(S.D./\sqrt{n}) < μ < Mean + 1.96(S.D./\sqrt{n})

=5.6 - 1.96(0.231) < μ < 5.6 + 1.96(0.231)

= 5.6 - 0.4528 < μ < 5.6 + 0.4528

= 5.15 < μ < 6.05

The 95% confidence interval provides more information because it has a larger interval.

Learn more about confidence intervals here:

brainly.com/question/14294413

#SPJ4

8 0
2 years ago
If f(x)=-4x^2-6x-1 and g(x)=-x^2-5x+3 find (f+g)(x) PLS ANSWER FAST!
arlik [135]
When you do (f+g)(x), all you have to do is take both functions and add them to each other. It should look like this when you set it up:
(f + g)(x) = (4x {}^{2}  - 6x - 1) + (x {}^{2}  - 5x + 3)
Then just add like terms and you should get:
(f + g)(x) = 5x {}^{2}  - 11x + 2
Hope this helped.
4 0
3 years ago
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