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Natalka [10]
3 years ago
8

In a sample of 56 eighth graders, 16 chose football As their favorite sport favorite sport. If there are 495 eight graders in th

e school, predict the number of Student who prefer football
Mathematics
1 answer:
Hoochie [10]3 years ago
8 0
<span>To answer this question, first find the percentage of eighth graders in the sample who chose football. To do this, take ratio of 16/56=.285 and rounding gives us .28 or 28%. Now, if we assume that the sample size reflects the attitudes of all the eighth graders in the school, we take 28% of the total number of eighth graders (495). Doing this we get .28 x 495 = 138.6 or rounding to get 139 students. 139 students are predicted to prefer football.</span>
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Step-by-step explanation:

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PLEASE HELP ASAP!!<br><br> Solve the equation below. <br> A. 196<br> B. 198<br> C. 243<br> D. 248
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The data below gives the mean price (in cents) of a liter of regular gasoline at self-service filling stations at a sample of si
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Answer:

135.05 ; 2.762 ; (133.201, 136.899) ; (132.840, 137.260)

Step-by-step explanation:

Given the data:

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Halifax 133.6

Montreal 136.2

Regina 132.3

Saskatoon 132.2

Yellowknife 138.9

Mean = (137.1 + 133.6 + 136.2 + 132.3 + 132.2 + 138.9) / 6

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Standard deviation (σ) : √Σ(X - mean)²/n-1

(137.1 - 135.05)^2 + (133.6 - 135.05)^2 + (136.2 - 135.05)^2 + (132.3 - 135.05)^2 + (132.2 - 135.05)^2+ (138.9 - 135.05)^2 = 38.135

√(38.135 / (6 - 1))

= √7.627

= 2.7617023

= 2.762

C.)

90% confidence interval of the mean :

Mean ± Zcrit * σ/√n

Zcrit at 90% = 1.64

135.05 ± 1.64 * (2.762/√6)

135.05 ± 1.64 * 1.1275817

Lower Value = (135.05 - (1.64 * 1.1275817)) = 133.201

Upper Value = (135.05 + (1.64 * 1.1275817))) = 136.899

Confidence interval = (133.201, 136.899)

D.)

95% confidence interval of the mean :

Mean ± Zcrit * σ/√n

Zcrit at 95% = 1.96

135.05 ± 1.96 * (2.762/6)

135.05 ± 1.96 * 1.1275817

Lower Value = (135.05 - (1.96 * 1.1275817)) = 132.840

Upper Value = (135.05 + (1.96 * 1.1275817)) = 137.260

Confidence interval = (132.840, 137.260)

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