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Oliga [24]
4 years ago
6

Orthogonal explanatory variables. suppose in the modelx2 to xk are all uncorrelated. such variables are called orthogonal variab

les. if this is the case:
a. what will be the structure of the (x’x) matrix?
b. how would you obtain = (x’x)−1x’y?
c. what will be the nature of the var–cov matrix of ?
d. suppose you have run the regression and afterward you want to introduce another orthogonal variable, say, xk 1 into the model. do you have to recompute all the previous coefficients 1 to k? why or why not?
Mathematics
1 answer:
sertanlavr [38]4 years ago
4 0
<span>d. suppose you have run the regression and afterward you want to introduce another orthogonal variable, say, xk 1 into the model. do you have to recompute all the previous coefficients 1 to k? why or why not?</span>
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Answer:

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Step-by-step explanation:

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Given that f(x) = x2 + 2x + 3 and g(x) = quantity of x plus four, over three , solve for f(g(x)) when x = 2.
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f(x)=x^2+2x+3
g(x)=\frac{x+4}{3}
f(g(x))=(\frac{x+4}{3})^2+2(\frac{x+4}{3})+3
f(g(x))=\frac{x^2+8x+16}{9}+\frac{2x+8}{3}+3
f(g(2))=\frac{2^2+8(2)+16}{9}+\frac{2(2)+8}{3}+3
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f(g(2))=4+4+3
f(g(2)=11

Check:
g(2)=(2+4)/3=2
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3 years ago
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You are the foreman of the Bar-S cattle ranch in Colorado. A neighboring ranch has calves for sale, and you are going to buy som
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Answer:

When you have two sets of data, one that represents an independent variable (X) and another that represents a dependent variable (Y) (it is a response of the first variable). A diagram called scatterplot can be generated to present the ordered pairs (X, Y) in the Cartesian plane to see how the two variables are related.

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The diagram can be seen in the attached file.

Step-by-step explanation:

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4. As shown in Figure 5.111 to the right if the
Juli2301 [7.4K]

Answer:

Area of the shaded part is 3.14 square unit.

Step-by-step explanation:

Area of the shaded part = Area of large semicircle - (Area of two small semi circles)

Area of large semicircle with center O = \frac{1}{2}(\pi r^2)

                                                                = \frac{1}{2}\pi (2)^{2}

                                                                = 2π

Area of semicircle with center O' = \frac{1}{2}\pi (1)^2

                                                      = \frac{\pi }{2}

Area of semicircle with center O" = \frac{\pi }{2}

Now substitute these values in the formula,

Area of shaded part = 2\pi - (\frac{\pi }{2}+\frac{\pi }{2})

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                                  = 3.14 square unit

Area of the shaded part is 3.14 square unit.

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