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posledela
3 years ago
11

Someone help me lolol

Mathematics
2 answers:
goldfiish [28.3K]3 years ago
8 0
-3/4, -4/6, |-4/5|, 0.802, 0.875
vazorg [7]3 years ago
4 0

Answer: the third option is correct.

Step-by-step explanation:

The largest negative number has the least value. That is -3/4.

It may help to convert the fractions to decimals. Remember that |absolute value| is considered positive in these questions.

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An isosceles triangle has slant height s and angle t opposite the base. Find a formula for the base length b in terms of the ang
Mars2501 [29]

OK, let's try with no figure.  We have an isosceles triangle sides s,s, and b.

Opposite b is angle t.

Draw the altitude h to bisect t.  We have two right triangles, legs b/2 and h, hypotenuse s.  The angle opposite b/2 is t/2 so

sin(t/2) = (b/2)/s = b/2s

So we arrived at the first part,

b = 2s sin(t/2)

The area of a triangle with sides s,s and included angle t is

A = (1/2) s² sin t

7 0
2 years ago
Which of the following sets of ordered pairs does not define a function? {(−1,4),(0,4),(1,4),(2,4),(3,4)} { ( − 1 , 4 ) , ( 0 ,
Novay_Z [31]

Step-by-step explanation:

5 is not function because an x cannot map on 2 different y's

6 0
3 years ago
Someone please help me out i don´t understand this question <br> ill give you 21 points
suter [353]

Answer:

0.67

Step-by-step explanation:

Formula: k = y/x

k = 2/3

k = 0.66666666666

k = 4/6

k= 0.66666666666

k = 6/9

k = 0.66666666666

k = 8/12

Round 0.67

Hence, answer = 0.67

[RevyBreeze]

8 0
2 years ago
Read 2 more answers
(1+cos2x)/(1-cos2x) = cot^2x
sesenic [268]

We will turn the left side into the right side.

\dfrac{1 + \cos 2x}{1 - \cos2x} = \cot^2 x

Use the identity:

\cos 2x = \cos^2 x - \sin^2 x

\dfrac{1 + \cos^2 x - \sin^2 x}{1 - ( \cos^2 x - \sin^2 x)} = \cot^2 x

\dfrac{1 - \sin^2 x + \cos^2 x }{1 - \cos^2 x + \sin^2 x} = \cot^2 x

Now use the identity

\sin^2 x + \cos^2 x = 1 solved for sin^2 x and for cos^2 x.

\dfrac{\cos^2 x + \cos^2 x }{\sin^2 x + \sin^2 x} = \cot^2 x

\dfrac{2\cos^2 x}{2\sin^2 x} = \cot^2 x

\dfrac{\cos^2 x}{\sin^2 x} = \cot^2 x

\cot^2 x = \cot^2 x


8 0
3 years ago
Find the surface area of the square pyramid using its net
Mamont248 [21]

Answer:

so basically this is easy if you break it down

Step-by-step explanation:

the triangle area= 5x4/2= 20/2= 10

there are 4 triangles so 10 x 4=40

square area= 5x5= 25

40+25= 65units^2

4 0
3 years ago
Read 2 more answers
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