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4 years ago

Suppose that the cost of renting a snowmobile is 37.50 for 5 hours.

Mathematics

2 answers:

Dominik [7]4 years ago

5 0

Answer:

Cost(c) is the dependent variable.

Step-by-step explanation:

The variable that we can change is called the Independent variable.

The dependent variable depends upon the independent variable, as we change the value of the independent variable the value of the dependent variable is also get changed.

Also, here since the cost of renting a snowmobile depends on the hours of renting a snowmobile.

Thus, Cost(c) is dependent variable and hours(h) is independent variable.

mojhsa [17]4 years ago

4 0

The dependent variable is c because the cost depends on how many hours you spend renting the snowmobile.

Brainliest please :)

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Assume that there is a 8% rate of disk drive failure in a year. a. If all your computer data is stored on a hard disk drive wit

romanna [79]

Answer:

0.9936 = 99.36% probability that during a year, you can avoid catastrophe with at least one working drive

Step-by-step explanation:

For each disk, there are only two possible outcomes. Either it works, or it does not. The probability of a disk working is independent of any other disk, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Assume that there is a 8% rate of disk drive failure in a year.

So 100 - 8 = 92% probability of working, which means that $p = 0.92$

Two disks are used:

This means that $n = 2$

What is the probability that during a year, you can avoid catastrophe with at least one working drive?

This is:

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.92)^{0}.(0.08)^{2} = 0.0064$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0064 = 0.9936$

0.9936 = 99.36% probability that during a year, you can avoid catastrophe with at least one working drive

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3 years ago

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andreev551 [17]

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3 years ago

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Kobotan [32]

Answer:

b answer

Step-by-step explanation:

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Answer:

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