Answer:
The standard deviation for the mean weigth of Salmon is 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount order stores.
Step-by-step explanation:
The mean sample of the sum of n random variables is

If
are indentically distributed and independent, like in the situation of the problem, then the variance of
will be the sum of the variances, in other words, it will be n times the variance of
.
However if we multiply this mean by 1/n (in other words, divide by n), then we have to divide the variance by 1/n², thus
and as a result, the standard deviation of
is the standard deviation of
divided by
.
Since the standard deviation of the weigth of a Salmon is 2 lbs, then the standard deviations for the mean weigth will be:
- Restaurants: We have boxes with 9 salmon each, so it will be

- Grocery stores: Each carton has 49 salmon, thus the standard deviation is

- Discount outlet stores: Each pallet has 64 salmon, as a result, the standard deviation is

We conclude that de standard deivation of the mean weigth of salmon of the types of shipment given is: 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount outlet stores.
Answer:
18cm
Step-by-step explanation:
We have the length of the rectangle but we need to find the width which we'll call w. Area is a, l is length.
a = l * w
20 = 5 * w
divide both sides by 5 to cancel the multiplication by 5 on the right side
4 = w
The rectangle is going to have two sides that are the length of l, and two sides that are the the length of w. We're looking for the perimiter p.
p = 2l + 2w
p = (2 * 5) + (2 * 4)
p = 18
Sold Last Month: 60 x
= 40
Remaining from last month: 60 - 40 = 20
Sold This Month: 20 x
= 8
Remaining from this month: 20 - 8 = 12
Answer: there are 12 houses left to be sold
Answer:
A = 2000(1.04)^t
Step-by-step explanation:
Using the compound interest formula;
A = P(1+r)^t
P is the principal = $2000
r is the rate = 4% = 0.04
On substituting
A = 2000(1+0.04)^t
A = 2000(1.04)^t
Hence the required expression is A = 2000(1.04)^t