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3 years ago

Suppose that the cost of renting a snowmobile is 37.50 for 5 hours.

Mathematics

2 answers:

Dominik [7]3 years ago

5 0

Answer:

Cost(c) is the dependent variable.

Step-by-step explanation:

The variable that we can change is called the Independent variable.

The dependent variable depends upon the independent variable, as we change the value of the independent variable the value of the dependent variable is also get changed.

Also, here since the cost of renting a snowmobile depends on the hours of renting a snowmobile.

Thus, Cost(c) is dependent variable and hours(h) is independent variable.

mojhsa [17]3 years ago

4 0

The dependent variable is c because the cost depends on how many hours you spend renting the snowmobile.

Brainliest please :)

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And this question please?

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Answer:

this would be 5

Step-by-step explanation:

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2 years ago

he radioactive element carbon-14 has a half-life of 5750 years. A scientist determined that the bones from a mastodon had lost

elena-s [515]

Answer:

The bones were 12,485 years old at the time they were discovered.

Step-by-step explanation:

Amount of the element:

The amount of the element after t years is given by the following equation, considering the decay rate proportional to the amount present:

$A(t) = A(0)e^{-kt}$

In which A(0) is the initial amount and k is the decay rate, as a decimal.

The radioactive element carbon-14 has a half-life of 5750 years.

This means that $A(5750) = 0.5A(0)$ , and we use this to find k. So

$A(t) = A(0)e^{-kt}$

$0.5A(0) = A(0)e^{-5750k}$

$e^{-5750k} = 0.5$

$\ln{e^{-5750k}} = \ln{0.5}$

$-5750k = \ln{0.5}$

$k = -\frac{\ln{0.5}}{5750}$

$k = 0.00012054733$

$A(t) = A(0)e^{-0.00012054733t}$

A scientist determined that the bones from a mastodon had lost 77.8 % of their carbon-14. How old were the bones at the time they were discovered?

Had 100 - 77.8 = 22.2% remaining, so this is t for which:

$A(t) = 0.222A(0)$

Then

$0.222A(0) = A(0)e^{-0.00012054733t}$

$e^{-0.00012054733t} = 0.222$

$\ln{e^{-0.00012054733t}} = \ln{0.222}$

$-0.00012054733t = \ln{0.222}$

$t = -\frac{\ln{0.222}}{0.00012054733}$

$t = 12485$

The bones were 12,485 years old at the time they were discovered.

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