Simplify.

\sqrt{ \frac{4x^{2} }{3y} }" alt=" \sqrt{ \frac{4x^{2} }{3y} }" align="absmiddle" class="latex-formula">
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Mathematics

1 answer:

Burka [1]3 years ago

4 0

$\sqrt{ \frac{4 x^{2} }{3y} } = \sqrt{ \frac{2^{2} x^{2}}{3y} } = \frac{ \sqrt{2^{2} x^{2}} }{ \sqrt{3y} } = \frac{2x}{ \sqrt{3y}}$

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Please help i need help geometry is very hard for me i am dumb

stiks02 [169]

Answer:

G. ABD = 74

H. DBC = 206

I. XYW = 33.75

J. WYZ = 46.25

Step-by-step explanation:

For G and H: You have a straight line (ABC) with another line coming off of it, creating two angles (ABD and DBC). A straight line has an angle of 180 degrees. This means that the two angles from the straight line when combined will give you 180 degrees. Solve for x.

ABD + DBC = ABC

(1/2x + 20) + (2x - 10) = 180

1/2x + 20 + 2x - 10 = 180

5/2x + 10 = 180

5/2x = 170

x = 108

Now that you have x, you can solve for each angle.

ABD = 1/2x + 20

ABD = 1/2(108) + 20

ABD = 54 + 20

ABD = 74

DBC = 2x - 10

DBC = 2(108) - 10

DBC = 216 - 10

DBC = 206

For I and J: For these problems, you use the same concept as before. You have a right angle (XYZ) that has within it two other angles (XYW and WYZ). A right angle has 90 degrees. Combine the two unknown angles and set it equal to the right angle. Solve for x.

XYW + WYZ = XYZ

(1 1/4x - 10) + (3/4x + 20) = 90

1 1/4x - 10 + 3/4x + 20 = 90

2x + 20 = 90

2x = 70

x = 35

Plug x into the angle values and solve.

XYW = 1 1/4x - 10

XYW = 1 1/4(35) - 10

XYW = 43.75 - 10

XYW = 33.75

WYZ = 3/4x + 20