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rosijanka [135]
4 years ago
11

Simplify.

\sqrt{ \frac{4x^{2} }{3y} }" alt=" \sqrt{ \frac{4x^{2} }{3y} }" align="absmiddle" class="latex-formula">
Show your work.
Mathematics
1 answer:
Burka [1]4 years ago
4 0
\sqrt{ \frac{4 x^{2} }{3y} } =  \sqrt{ \frac{2^{2} x^{2}}{3y} } =  \frac{ \sqrt{2^{2} x^{2}} }{ \sqrt{3y} } = \frac{2x}{ \sqrt{3y}}
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(3,6) (5,8)?____________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________                                                                                                                                                                                                                                                                                                       
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