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2 years ago

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A candy company provides samples of fudge and truffles to their store visitors. The manager authorized the store to distribute u

p to 50 pieces of candy. The store expects to give away at least 20 pieces of fudge and at least 15 truffles

1 answer:

mrs_skeptik [129]2 years ago

7 0

Answer:

hdhufhduh

Step-by-step explanation:

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An office opens at 9am and closes at 5.30pm with a lunch break of 30minutes. What is the ratio of lunch break to the total perio

Alex777 [14]

Answer:

1:17

Step-by-step explanation:

Find out how long it it between 5.30pm and 9am. This is 8 hours 30 minutes or 510 minutes.

Now, arrange them in the ratio of Lunch Break to Total office time

30:510. This can be simplified to 1:17

Please check if the question is worded correctly, just in case. Because ratio questions are usually based on a part and the remaining parts of the same thing, and not part to whole.

Anyway. The answer given if for the question you have typed.

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A merchant sold a pen for $6.90 ,thereby making a profit of 15% on her cost calculate the cost of the pen to the merchant to the

NeTakaya

So you know the merchant made a 15% profit on the pen, so she bought it for a cheaper price. To find the cost of the pen before you have to take the price now, $6.90 and times it by 85%. You do 85% because you subtract the 15% she saved from 100% and you get 85%. So 6.90x.85= 5.865 which rounds to $5.87

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3 years ago

If you help me I’ll mark brainliest

Dafna11 [192]

Answer:

1= 2x+74

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3 years ago

0 A maker of a certain brand of low-fat cereal bars claims that the average saturated fat content is 0.5 gram. In a random sampl

balandron [24]

Answer:

<em>The first step is to determine the average </em>

$x= \frac{0,6+0,7+ 0,7+0,3+0,4+ 0,5+ 0,4 +0,2}{8}\\\ x= 0,475$

<em>The exercise says it’s a normal distribution: (n=8)</em>

$s^{2}= \frac{1}{n-1} ((0,6.x)^2+2(0,7-x)^2+(0.3-x)^2+2(0.4-x)^2+(0.5-x)^2+(0.2-x)^2)\\\ \frac{1}{7}*0,235 = 0,0336 \\\\ s= 0183$

<em>According to the exercise, the mean is equal to 0,5 then the value of t of the distribution can be obtained </em>

<em />

$t= \frac{x-u}{\frac{s}{\sqrt{n} }}\\\ t= \frac{0,475 - 0,5}{0,183}\\\ t= -0,3860$

<em>The variable t has 7 grade to liberty, we calculate the p-value as: </em>

$2* P(t < - 0,3860)= \\\ 2* 0,3554 = 0,7108$

This value is very high, therefore the hypothesis is not rejected

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3 years ago

Pls help I’ll brainlest <br><br> Complete the activities below

DanielleElmas [232]

Answer:

Step-by-step explanation:

( $x_{1}$ , $y_{1}$ )

( $x_{2}$ , $y_{2}$ )

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2 years ago