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miv72 [106K]
3 years ago
13

If gravity did not affect the pain of a horizontally thrown ball the ball would

Physics
2 answers:
Liono4ka [1.6K]3 years ago
8 0
If gravity did not affect a horizontally thrown ball, the ball would continue along its horizontal path indefinitely (assuming it is thrown in a vacuum so no other forces are acting on it).
Drupady [299]3 years ago
4 0

If gravity had no effect on a ball after you threw it ... and there also
were no air to slow it down ... then the ball would continue traveling
in a straight line, in whatever direction you threw it. 

That's the heart and soul of Newton's laws of motion ... any object
keeps moving at the same speed, and in a straight line in the same
direction, until a force acts on it to change its speed or direction.\

If you threw the ball horizontally, then it would keep moving in the
same direction you threw it.  But don't forget:  The Earth is not flat.
The Earth is a sphere.  So, as the ball kept going farther and farther
in the same straight line, the Earth would curve away from it, and it
would look like the ball is getting farther and farther from the ground.
 
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Which part of Earth Is hotter ? Which part is colder ? Why ?
LekaFEV [45]

Explanation:

Dasht-e Loot, Iran is the hottest,, and the coldest is the East Antarctic Plateau. The reason that part of Iran is the hottest is because it's near the Arabian deserts, and as you know the deserts can be pretty hot. The coldest part of the Earth is that cold because it doesn't get as much sunlight, the reason for that is because they don't get any direct sunlight.

5 0
4 years ago
If a car has a velocity of 85 km/hr, how long will it take to accelerate to 45 km/hr if the acceleration is -3 km/hr/sec?
weqwewe [10]

Answer:

Time, t = 13.34 seconds.

Explanation:

Given the following data;

Initial velocity, u = 85km/hr to meters per seconds = 85*1000/3600 = 23.61 m/s

Final velocity, v = 45km/hr to meters per seconds = 45*1000/3600 = 12.5 m/s

Acceleration, a = -3 km/hr/sec to meters per seconds square = -3*1000/3600 = -0.833m/s²

To find the time;

Acceleration = (v - u)/t

-0.833 = (12.5 - 23.61)/t

-0.833t = -11.11

t = 11.11/0.833

Time, t = 13.34 seconds.

6 0
3 years ago
Ở nhiệt độ không đổi, dưới áp suất 10^4 Pa l, một lượng khí có thể tích 10l. Tính thể tích lượng khí đó dưới áp suất 5.10^4 Pa
gtnhenbr [62]

Answer:

Thể tích cuối cùng, V2 = 2 L

Explanation:

Cho các dữ liệu sau đây;

Khối lượng ban đầu = 10 L

Áp suất ban đầu = 10⁴ = 10000 Pa

Áp suất cuối cùng = 5 * 10⁴ = 50000 Pa

Để tìm tập mới hoặc tập cuối cùng, chúng ta sẽ sử dụng định luật Boyle;

Để tìm tập mới V2, chúng tôi sẽ sử dụng định luật Boyles.

Boyles phát biểu rằng khi nhiệt độ của khí lý tưởng được giữ không đổi, áp suất của khí tỉ lệ nghịch với thể tích mà khí chiếm giữ.

Về mặt toán học, định luật Boyles được đưa ra bởi;

PV = K

P_{1}V_{1} = P_{2}V_{2}

Thay vào phương trình, ta có;

10000 * 10 = 50000V_{2}

100000 = 50000V_{2}

V_{2} = \frac {100000}{50000}

V_{2} = 2

Thể tích cuối cùng, V2 = 2 L

6 0
3 years ago
A merry go round exerts a force of 1000 N on a rider on the
SVEN [57.7K]

Answer:

The radius of the circle made by the person on the merry go round is 74.55 meters

Explanation:

The given parameters are;

The force the merry go round exerts on the rider = 1000 N

The time it takes the merry go round to make one complete revolution = 15 seconds

The weight of the person = 750 N

The radius of the circle made by the person on the merry go round = r

We have;

F_c = \dfrac{m \cdot v^2}{r} = m \cdot \omega ^2 \cdot r

Where;

m = The mass of the person

v = The velocity of the person

F_c = The centrifugal force acting on the person = 1,000 N

r = The radius of the circle made by the person on the merry go round

ω = Angular velocity = 2·π/15 rad/s

We have;

The mass of the person = The weight/(The acceleration due to gravity, g)

∴ The mass of the person = 750/9.81 ≈ 76.45 kg

By substituting the calculated and known values into the equation for  the centripetal force, we have;

F_c = m × ω² × r

1000 = 76.45 × (2·π/15)² × r

r = 1000/(76.45 × (2·π/15)²) = 74.55 m

The radius of the circle made by the person on the merry go round = r = 74.55 m.

3 0
3 years ago
the earth's moon has a gravitational field strength of about 1.6 n/kg near its surface. the moon has a mass of 7.35x10^22 kg. wh
Andrew [12]

Answer:

1750km

Explanation:

8 0
3 years ago
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