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miv72 [106K]
3 years ago
13

If gravity did not affect the pain of a horizontally thrown ball the ball would

Physics
2 answers:
Liono4ka [1.6K]3 years ago
8 0
If gravity did not affect a horizontally thrown ball, the ball would continue along its horizontal path indefinitely (assuming it is thrown in a vacuum so no other forces are acting on it).
Drupady [299]3 years ago
4 0

If gravity had no effect on a ball after you threw it ... and there also
were no air to slow it down ... then the ball would continue traveling
in a straight line, in whatever direction you threw it. 

That's the heart and soul of Newton's laws of motion ... any object
keeps moving at the same speed, and in a straight line in the same
direction, until a force acts on it to change its speed or direction.\

If you threw the ball horizontally, then it would keep moving in the
same direction you threw it.  But don't forget:  The Earth is not flat.
The Earth is a sphere.  So, as the ball kept going farther and farther
in the same straight line, the Earth would curve away from it, and it
would look like the ball is getting farther and farther from the ground.
 
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It's called deposition. 
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3 years ago
A cylinder with a moving piston expands from an initial volume of 0.250 L against an external pressure of 2.00 atm. The expansio
Step2247 [10]

The final volume of the gas is 144.25 L

Explanation:

For an ideal gas kept at constant pressure, the work done by the gas on the surroundings is given by

W=p\Delta V = p(V_f - V_i)

where

p is the pressure of the gas

V_i is the initial volume

V_f is the final volume

For the gas in the cylinder in this problem,

p = 2.00 atm

V_i = 0.250 L

And we also know the work done,

W = 288 J

So we can solve the equation for V_f, the final volume:

V_f = V_i + \frac{W}{p}=0.250 + \frac{288}{2.00}=144.25 L

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3 years ago
What two factors determine the amount of friction there will be between objects?
barxatty [35]

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3 years ago
Water (density = 1 ´ 103 kg/m3) flows at 10 m/s through a pipe with radius 0.030 m. the pipe goes up to the second floor of the
Hatshy [7]

density of water = 1000 kg/m^3

velocity of flow = 10 m/s

radius of pipe = 0.030 m

Height of second floor = 2 m

Now we can use here Bernuoli's Equation to find the speed of water flow at second floor

P_1 + 1/2\rho v_1^2 + \rho g h_1= P_2 + 1/2 \rho v_2^2 + \rho g h_2

P + 1/2 * 1000 * 10^2 + 1000* 9.8 * 0 = P + 1/2 * 1000 * v^2 + 1000*9.8*2

v = 7.8 m/s

Now in order to find the radius of pipe we can use equation of continuity

A_1 v_1 = A_2 v_2

\pi *0.030^2 * 10 = \pi * r^2 * 7.8

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3 years ago
How do clouds become stars ?
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Stars form inside relatively dense concenstrations of interstellar gas and dust known as molecular clouds.





hope it helps
3 0
3 years ago
Read 2 more answers
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