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tino4ka555 [31]
2 years ago
5

15.0 kg mass is displaced 3.00 m south and then 4.00 m west by a 10.0 N force. What is the total work done on the object?

Physics
1 answer:
masha68 [24]2 years ago
5 0
<h2>Answer: D. 70.0 J</h2>

Explanation:

3.00 m + 4.00 m = 7.00 m x 10.0 N = 70.0 J

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Answer:

The distance covered by the rocket after fuel ran out is 3442.04 m

Explanation:

Given that the rocket moves with an acceleration a=30m/s^2

time t=5 s

Since the rocket starts from rest initial velocity  u=0 s

The distance it travelled within this time is given by  s=ut+ \frac{1}{2} at^2                                                                                                  =0 \times 5+ \frac{1}{2} (30\times25)=375 m

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Thus it travels 15.3 seconds more after fuel running out. The distance covered during this period is given

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3 years ago
At NASA's Zero Gravity Research Facility in Cleveland, Ohio, experimental payloads fall freely from rest in an evacuated vertica
Diano4ka-milaya [45]

Answer:

(a). Energy is 64,680 J

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Explanation:

(a).

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\dfrac{51.43m}{s} * \dfrac{3600s}{hr} * \dfrac{1mile}{1609.34m}

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