Answer:
4m/s2
Explanation:
acceleration=v-u/t...v=12m/s,u=0m/s,t=3sec
a=12-0/3
=4m/s2
Three times larger I think.
Answer:
v = 10 m/s
Explanation:
Given that,
Distance covered by a sprinter, d = 100 m
Time taken by him to reach the finish line, t = 10 s
We need to find his average velocity. We know that velocity is equal to the distance covered divided by time taken. So,
v = d/t

Hence, his average velocity is 10 m/s.
The distance that would be accumulated during the journey is 2.5 meters
The parameters given in the question are written below;
average speed= 5 km/hr
time = 30 minutes
convert 30 minutes to hours
= 30/60
= 0.5 hours
Distance-= speed × time
= 5 × 0.5
= 2.5 meters
Hence the distance of the entire journey is 2.5 meters
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Answer:
500 N
Explanation:
Since the work done on the spring W = Fx where F = force applied and x = compression length = 0.170 m (since the spring will be compressed its full length when the force is applied)
Since W = 85.0 J and we need to find F,
F = W/x
= 85.0 J/0.170 m
= 500 N
So, the magnitude of force must you apply to hold the platform stationary at the final distance given above is 500 N.