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Lady_Fox [76]
3 years ago
12

Two speakers face each other, and they each emit a sound of wavelength λ. One speaker is 180∘ out of phase with respect to the o

ther. If we separate the speakers by a distance 1.5λ, how far from the left-most speaker should we place a microphone in order to pick up the loudest sound? Ignore reflections from nearby surfaces. Select all that apply.a. 3/4λb. 0 λc. 1/2λd. 1/4λe. 1 λ

Physics
1 answer:
mel-nik [20]3 years ago
4 0

Answer:

a. 3/4λ

d. 1/4λ

Explanation:

When the wavelength of the sound waves is λ and the two waves are having same frequency the waves are said to be out of phase if their phase difference is in the multiples of \frac{\lambda}{2} or 180°.

When the two waves are out of phase then their opposite maxima coincide at the same time resulting in the minimum amplitude of the resulting wave throughout.

  • As we observe from the schematic that the a wave has sinusoidal pattern of variation and we get a maxima after each \frac{\lambda}{4} of the distance.
  • Here we have two speakers out of phase therefore on shifting one of the speakers by the odd multiples of \frac{\lambda}{2} we have the maxima or the extreme amplitudes.

So, we must place the microphone at  3/4λ and 1/4λ to pickup the loudest sound.

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Velocity and wavelength are directly proportional when frequency is kept constant.

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