Answer:
2.73×10¯³⁴ m.
Explanation:
The following data were obtained from the question:
Mass (m) = 0.113 Kg
Velocity (v) = 43 m/s
Wavelength (λ) =?
Next, we shall determine the energy of the ball. This can be obtained as follow:
Mass (m) = 0.113 Kg
Velocity (v) = 43 m/s
Energy (E) =?
E = ½m²
E = ½ × 0.113 × 43²
E = 0.0565 × 1849
E = 104.4685 J
Next, we shall determine the frequency. This can be obtained as follow:
Energy (E) = 104.4685 J
Planck's constant (h) = 6.63×10¯³⁴ Js
Frequency (f) =?
E = hf
104.4685 = 6.63×10¯³⁴ × f
Divide both side by 6.63×10¯³⁴
f = 104.4685 / 6.63×10¯³⁴
f = 15.76×10³⁴ Hz
Finally, we shall determine the wavelength of the ball. This can be obtained as follow:
Velocity (v) = 43 m/s
Frequency (f) = 15.76×10³⁴ Hz
Wavelength (λ) =?
v = λf
43 = λ × 15.76×10³⁴
Divide both side by 15.76×10³⁴
λ = 43 / 15.76×10³⁴
λ = 2.73×10¯³⁴ m
Therefore, the wavelength of the ball is 2.73×10¯³⁴ m.
Answer:
1-D(carbon dioxide, water and sunlight)
2-D(parasitism)
3-C(competition)
Explanation:
hope it helps
The kinetic energy and potential energy are the two types of the mechanical energy. The generators are used to produce electricity, which is basically the electrical energy. Hence, the generators convert kinetic energy (mechanical energy) into the electrical energy which is supplied to our homes.
Hence, the correct answer is: Mechanical energy to the Electrical energy
The work done by the pushing force is 200 J; option B.
<h3>What is work done in an inclined plane?</h3>
The work done in an inclined plane is given by the formula below:
- Work done = Force * distance
Force, F = mgsinθ + ma
where a = 0
Work done = 80 * 5 * sin 30°
Work done = 200 J
In conclusion, work done is the product of force and distance.
Learn more about work done at: brainly.com/question/10712853
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Hello
This question requires us to deal with the football as a projectile. Therefore, we will assume that the ball is caught at the same height from which it was thrown.
To see how far the ball will travel, we use the formula for the range of a projectile that is:
Range = [(initial velocity)^2 * sin(2*angle to horizontal)]/g
Given that the initial velocity is 16 m/s, the angle to the horizontal is 25 and g is 9.81 m/s^2, R works out to be:
almost 20.0 m
The distance the receiver will have to run will be:
20 - 16.5 = 3.5 m
The time of the ball's flight will be equal to the time the receiver has to get to the ball. The ball's flight time is given by:
time = [2 * (initial velocity) * sin(angle from horizontal)] / g
time = 1.38 seconds
Therefore, the receiver's speed must be:
3.5 / 1.38 = 2.54 m/s