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sweet-ann [11.9K]
3 years ago
13

As of the due date, your progress bar shows that you have completed 80% of a SmartBook assignment. After the assignment due date

, you return to SmartBook and complete the remaining 20% of the assignment. What score appears on your Connect reports?
Mathematics
1 answer:
inessss [21]3 years ago
4 0

Answer:

80%

Step-by-step explanation:

The Score on the Connect reports show the level of complation of the SmartBook assignment till the due date.

Thus, the work done after the due date is not reflected in the Connect reports score.

Since you have completed 80% of the assignment <em>before</em> the due date, your score is 80%

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In a box there are six envelopes each containing two cards. Three of the envelopes contain two red cards, two of them contain a
Sphinxa [80]

Answer:

\frac{2}{5}

Step-by-step explanation:

3 envelopes having 2 red card

2 envelopes having 1 red card and 1 black card

1 envelope having 2 black cards

We are given that . An envelope is selected at random and a card is withdrawn and found to be red.

So, No. of ways of envelope having red card = 3+2 = 5

No. of required ways of envelope having 1 red card and 1 black card = 2

So, probability of getting an envelope having 1 red card and 1 black card = \frac{2}{5}

Hence The chance the other card is black is \frac{2}{5}

5 0
3 years ago
How many years will it take for a sum of money to double at 10% compounded annually
Bond [772]

Answer:

t=7.27 years

Step-by-step explanation:

Let the money be p and t will be the number of years that will be needed for the money to get double.

ATQ, 2p=p*(1+0.1)^t

2=(1.1)^t

log(2)/log(1.1)=t, t=7.27

5 0
3 years ago
3x - 4y = 7
Alina [70]
      3x - 4y = 7
    -(3x + 2y = -5)

=     0 - 6y = 12
          -6y = 12
             y = -2
The resulting equation would be y = -2.

4 0
3 years ago
Read 2 more answers
Marlon asks a friend to think of a number from 5 to 11. What is the probability that Marlon’s friend will think of the number 9?
Strike441 [17]

Answer:

1/7

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
(1 point) Each of the following statements is an attempt to show that a given series is convergent or divergent not using the Co
kvv77 [185]

Answer:

I.

CORRECT.

II.

CORRECT.

III.

CORRECT.

IV.

CORRECT.

V.

INCORRECT.

VI.

CORRECT

Step-by-step explanation:

To understand let us restate the comparison test in simple terms.

Comparison test :

Given     \text{Series}_A   and \text{Series}_B such that    \text{Series}_A < \text{Series}_B , then

1.   If    \text{Series}_B converges then \text{Series}_A  converges as well.

2.  If  \text{Series}_A  diverges then \text{Series}_B  diverges as well.

Now to give you a more intuitive idea of what is going on, think about it like this.  When   the series on top converges it is like an "upper bound" for what you have on the bottom, therefore what you have on the bottom has to converge as well.

Similarly if what you have on the bottom explotes, then what you have on top will explote as well.

That's how I like to think about that intuitively.

Now, using those results let us examine the statements.

I.

\frac{1}{n} < \frac{ln(n)}{n}

Since the infinite sum of 1/n  diverges in fact the infinite sum of ln(n)/n does not converge.

Therefore, CORRECT.

II.

\frac{\arctan(n)}{n^3} < \frac{\pi}{2}\frac{1}{n^3}  

Since the infinite sum of    \frac{\pi}{2}\frac{1}{n^3}   is in fact convergent then  \frac{\arctan(n)}{n^3} converges as well using the comparison theorem. Therefore

CORRECT.

III.

\frac{n}{2-n^3} < \frac{1}{n^2}

Once again   1/n^2  does converge so what you have on the bottom converges as well. Therefore

CORRECT.

IV.

\frac{\ln(n)}{n^2} < \frac{1}{n^{1.5}}

Once again   \frac{1}{n^{1.5}}  converges therefore since it is on top what is on the bottom converges as well. Therefore.

CORRECT.

V.

\frac{\ln(n)}{n} < \frac{2}{n}

Now the fact that  \frac{2}{n}    diverges does not necessarily imply that what you have on the bottom diverges. Therefore

INCORRECT.

VI.

That is correct as well since what you have on top converges therefore what you have on the bottom converges as well.

 

6 0
3 years ago
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