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Answer is: 4.0 mol of lithium nitride would be produced.
Balanced chemical reaction: 6Li + N₂ → 2Li₃N.
n(Li) = 12 mol; amount of substance.
From chemical reaction: n(Li) : n(Li₃N) = 6 : 2 (3 : 1).
n(Li₃N) = n(Li) ÷ 3.
n(Li₃N) = 12 mol ÷ 3.
n(Li₃N) = 4 mol; amount of lithium nitride.
Answer:
90.37 g
Explanation:
From Avogadro Number,
1 mole of every substance contains a particle number of 6.02×10²³
From the question,
1 mole of CH₄ contains 6.02×10²³ molecules.
But,
1 mole of CH₄ has a mass of 16 g
Therefore,
16 g of CH₄ contains 6.02×10²³ molecules
Then,
Y g will contain 3.4×10²⁴ molecules
Solve for Y
Y = (16× 3.4×10²⁴)/(6.02×10²³)
Y = 90.37 g
Answer:
Molarity = 0.95 mol/dm³
Explanation:
Given data:
Volume of H₂SO₄ = 15.8 cm³
Volume of NaOH = 20 cm³
Concentration of NaOH = 1.5 mol/dm³
Concentration of H₂SO₄ = ?
Solution:
Chemical equation:
NaOH + H₂SO₄ → Na₂SO₄ + H₂O
First of all we will calculate the number of moles of NaOH and for that we will convert the units first,
Volume = 20 cm³/1000 = 0.02 L
Concentration of NaOH = 1.5 mol/dm³
1 mol/dm³ = 1 mol/L
Concentration of NaOH = 1.5 mol/L
Number of moles of NaOH:
Molarity = number of moles / volume in L
1.5 M = number of moles / 0.02 L
Number of moles = 1.5 M ×0.02 L
Number of moles = 0.03 mol
Now we will compare the moles of NaOH and H₂SO₄
NaOH : H₂SO₄
2 : 1
0.03 : 1/2×0.03 = 0.015 mol
Concentration of H₂SO₄:
Volume of H₂SO₄:
15.8 cm³/1000 = 0.0158 L
Molarity = number of moles / volume in L
Molarity = 0.015 mol / 0.0158 L
Molarity = 0.95 mol/L
1 mol/L = 1 mol/dm³
Molarity = 0.95 mol/dm³
