"The Number of solute particles increases". Answer choice "A". #PLATOLIVEZMATTTER.
Fire extinguishers and fire blankets are used when fires are in a lab
Answer:
The mass of reactants and products for the reaction is this:
- 92 g Na, 32 g O₂, 124 g Na₂O
which is not a choice from the list.
Explanation:
4 moles of Na reacts with 1 mol of oxygen to produce 2 moles of sodium oxide.
Na = 23 g/m
4 moles are (4 . 23) = 92 g
O₂ = 32 g/m
It's a diatomic molecule (each O is 16 g/m)
Na₂O = 62 g/m
2 mol of sodium oxide will be (2 .62) = 124 grams
The mass of reactants and products for the reaction is this:
- 92 g Na, 32 g O₂, 124 g Na₂O
which is not a choice from the list.
<u>Answer:</u> The volume of concentrated solution required is 9.95 mL
<u>Explanation:</u>
To calculate the pH of the solution, we use the equation:
![pH=-\log[H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D)
We are given:
pH = 0.70
Putting values in above equation, we get:
![0.70=-\log[H^+]](https://tex.z-dn.net/?f=0.70%3D-%5Clog%5BH%5E%2B%5D)
![[H^+]=10^{-0.70}=0.199M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D10%5E%7B-0.70%7D%3D0.199M)
1 mole of nitric acid produces 1 mole of hydrogen ions and 1 mole of nitrate ions.
Molarity of nitric acid = 0.199 M
To calculate the volume of the concentrated solution, we use the equation:

where,
are the molarity and volume of the concentrated nitric acid solution
are the molarity and volume of diluted nitric acid solution
We are given:

Putting values in above equation, we get:

Hence, the volume of concentrated solution required is 9.95 mL