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ra1l [238]
3 years ago
10

What do colligative properties depend on?

Chemistry
2 answers:
oee [108]3 years ago
5 0
Colligative properties depend on the amount of solute dissolved in a solvent. These set of properties do not depend on the type of species present. These properties include freezing point depression, boiling point elevation, osmotic pressure and vapor pressure lowering.
natta225 [31]3 years ago
4 0

Answer:

Colligative properties depend on the quantity of solute and solvent and the identity of the solvent.

Explanation:

Colligative properties are defined as a set of intensive physical properties that result from the interactions between solute and solvent that form a solution. In this group of properties, we can find the <em>freezing point depression, boiling point elevation, osmotic pressure, and vapor pressure lowering.</em>

The mentioned properties dependon the amount of solute and solvent (concentration) and the nature of the solvent. this fact can be pictured by the freezing point depression formula:

T_{f} _{solvent} -T_{f} _{solution}  = K_{f}   _{x}   m

where T_{f} _{solvent} is the freezing point of the pure solvent, T_{f} _{solution} is the freezing point of the solution, K_{f} is the freezing point depression constant  and m is the molality

In the equation, it can be seen that the change of temperature of the solution with respect to the pure solvent depends on the molality, which is the ratio of moles of solute and mass of solvent. Moreover, the change also depends on the freezing point depression constant that is a characteristic of the solvent.

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Cloud [144]

Answer:

answer is c

Explanation: cause there breaking it

8 0
3 years ago
A rigid container is filled with chlorine gas. The gas has a pressure of 2.75 bar. The tank is then cooled down to -20.0oC at wh
Gnom [1K]

Answer:

Original temperature (T1) = - 37.16°C

Explanation:

Given:

Gas pressure (P1) = 2.75 bar

Temperature (T2) = - 20°C

Gas pressure (P2) = 1.48 bar

Find:

Original temperature (T1)

Computation:

Using Gay-Lussac's Law

⇒ P1 / T1 = P2 / T2

⇒ 2.75 / T1 = 1.48 / (-20)

⇒ T1 = (2.75)(-20) / 1.48

⇒ T1 = -55 / 1.48

⇒ T1 = - 37.16°C

Original temperature (T1) = - 37.16°C

3 0
3 years ago
29. If a walnut is burned in a
harkovskaia [24]

Energy were released from the walnut, q = 1,673.6 J

<h3>Equation :</h3>

To find the energy using formula,

q = mcΔt

where,

q is charge

m is mass

c is specific heat of water

Δt is change in temperature

So, given

t₁ = 50°C

t₂ = 60°C

m = 40g

c = 4.184 J/g

Now putting the values known,

We get,

q = mc(t₂ - t₁)

q = 40g x 4.184 J/g x  (60 - 50)

q = 167.36 J x 10

q = 1,673.6 J

<h3>What is heat energy?</h3>

Heat is the thermal energy that is transferred when two systems with different surface temperatures come into contact. Heat is denoted by the letters q or Q and is measured in Joules.

To know more about specific heat :

brainly.com/question/11297584

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8 0
1 year ago
Plants, plant life cycles, photosynthesis, plant parts, plant growth is what branch of science
WARRIOR [948]
The study of plants, plant life cycles, photosynthesis, plant parts, etc. is under botany (study of plants).
4 0
2 years ago
g For the reaction Ag2S(s)⇌2Ag+(aq)+S2−(aq)Ag2S(s)⇌2Ag+(aq)+S2−(aq), Keq=2.4×10−4Keq=2.4×10−4, and the equilibrium concentration
Roman55 [17]

Answer:

0.32 M

Explanation:

Step 1: Write the balanced reaction at equilibrium

Ag₂S(s) ⇌ 2 Ag⁺(aq) + S²⁻(aq)

Step 2: Calculate the concentration of Ag⁺ at equilibrium

We will use the formula for the concentration equilibrium constant (Keq), which is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. It only includes gases and aqueous species.

Keq = [Ag⁺]² × [S²⁻]

[Ag⁺] = √{Keq / [S²⁻]}

[Ag⁺] = √{2.4 × 10⁻⁴ / 0.0023} = 0.32 M

8 0
3 years ago
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