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ra1l [238]
3 years ago
10

What do colligative properties depend on?

Chemistry
2 answers:
oee [108]3 years ago
5 0
Colligative properties depend on the amount of solute dissolved in a solvent. These set of properties do not depend on the type of species present. These properties include freezing point depression, boiling point elevation, osmotic pressure and vapor pressure lowering.
natta225 [31]3 years ago
4 0

Answer:

Colligative properties depend on the quantity of solute and solvent and the identity of the solvent.

Explanation:

Colligative properties are defined as a set of intensive physical properties that result from the interactions between solute and solvent that form a solution. In this group of properties, we can find the <em>freezing point depression, boiling point elevation, osmotic pressure, and vapor pressure lowering.</em>

The mentioned properties dependon the amount of solute and solvent (concentration) and the nature of the solvent. this fact can be pictured by the freezing point depression formula:

T_{f} _{solvent} -T_{f} _{solution}  = K_{f}   _{x}   m

where T_{f} _{solvent} is the freezing point of the pure solvent, T_{f} _{solution} is the freezing point of the solution, K_{f} is the freezing point depression constant  and m is the molality

In the equation, it can be seen that the change of temperature of the solution with respect to the pure solvent depends on the molality, which is the ratio of moles of solute and mass of solvent. Moreover, the change also depends on the freezing point depression constant that is a characteristic of the solvent.

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I need help ASAP please<br> Calculating pH<br> See chart below
laila [671]

Answer:

12, basic, 9, basic

Explanation:

pH = -log[H+]

Using the data in the table, you can calculate the pH:

-log[1e-12] = 12

-log[1e-9] = 9

To find out whether it is acidic, basic, or neutral, use a pH scale. Anything less than 7 is acidic, anything over is basic. Knowing this, both will be basic.

5 0
3 years ago
When 231. mg of a certain molecular compound X are dissolved in 65. g of benzene (CH), the freezing point of the solution is mea
Elan Coil [88]

Answer:

Molar mass X = 18.2 g/mol

Explanation:

Step 1: Data given

Mass of compound X = 231 mg = 0.231 grams

Mass of benzene = 65.0 grams

The freezing point of the solution is measured to be 4.5 °C.

Freezing point of pure benzene = 5.5 °C

The freezing point constant for benzene is 5.12 °C/m

Step 2: Calculate molality

ΔT = i*Kf*m

⇒ΔT = the freezing point depression = 5.5 °C - 4.5 °C = 1.0 °C

⇒i = the Van't hoff factor = 1

⇒Kf = the freezing point depression constant for benzene = 5.12 °C/m

⇒m = the molality = moles X / mass benzene

m = 1.0 / 5.12 °C/m

m = 0.1953 molal

Step 3: Calculate moles X

Moles X = molality * mass benzene

Moles X = 0.1953 molal * 0.065 kg

Moles X = 0.0127 moles

Step 4: Calculate molar mass X

Molar mass X = mass / moles

Molar mass X = 0.231 grams / 0.0127 moles

Molar mass X = 18.2 g/mol

5 0
3 years ago
Which physical property does the inventor need to consider when choosing a
adelina 88 [10]

Answer:

A.

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Explanation:

Ductility

6 0
4 years ago
What is the net ionic equation resulting from a reaction of aqueous solutions of nitric acid and sodium hydroxide?
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Answer:

equals ABC

Explanation:

4 0
3 years ago
a 10g cookie is burned in a calorimeter causing the temperature of 20 g water to change from 3°C to 5°C, What us the energy cont
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Answer:

30 g. 8'C

Explanation:

the 10 g is plus the fact that I have to help you get the chance to get the answer

5 0
3 years ago
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