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ra1l [238]
3 years ago
10

What do colligative properties depend on?

Chemistry
2 answers:
oee [108]3 years ago
5 0
Colligative properties depend on the amount of solute dissolved in a solvent. These set of properties do not depend on the type of species present. These properties include freezing point depression, boiling point elevation, osmotic pressure and vapor pressure lowering.
natta225 [31]3 years ago
4 0

Answer:

Colligative properties depend on the quantity of solute and solvent and the identity of the solvent.

Explanation:

Colligative properties are defined as a set of intensive physical properties that result from the interactions between solute and solvent that form a solution. In this group of properties, we can find the <em>freezing point depression, boiling point elevation, osmotic pressure, and vapor pressure lowering.</em>

The mentioned properties dependon the amount of solute and solvent (concentration) and the nature of the solvent. this fact can be pictured by the freezing point depression formula:

T_{f} _{solvent} -T_{f} _{solution}  = K_{f}   _{x}   m

where T_{f} _{solvent} is the freezing point of the pure solvent, T_{f} _{solution} is the freezing point of the solution, K_{f} is the freezing point depression constant  and m is the molality

In the equation, it can be seen that the change of temperature of the solution with respect to the pure solvent depends on the molality, which is the ratio of moles of solute and mass of solvent. Moreover, the change also depends on the freezing point depression constant that is a characteristic of the solvent.

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The heats of combustion of ethane (C2H6) and butane (C4H10) are 52 kJ/g and 49 kJ/g, respectively. We need to produce 1.000 x 10
LekaFEV [45]

Answer :

(1) The number of grams needed of each fuel (C_2H_6)\text{ and }(C_4H_{10}) are 19.23 g and 20.41 g respectively.

(2) The number of moles of each fuel (C_2H_6)\text{ and }(C_4H_{10}) are 0.641 moles and 0.352 moles respectively.

(3) The balanced chemical equation for the combustion of the fuels.

C_2H_6+\frac{7}{2}O_2\rightarrow 2CO_2+3H_2O

C_4H_{10}+\frac{13}{2}O_2\rightarrow 4CO_2+5H_2O

(4) The number of moles of CO_2 produced by burning each fuel is 1.28 mole and 1.41 mole respectively.

The fuel that emitting least amount of CO_2 is C_2H_6

Explanation :

<u>Part 1 :</u>

First we have to calculate the number of grams needed of each fuel (C_2H_6)\text{ and }(C_4H_{10}).

As, 52 kJ energy required amount of C_2H_6 = 1 g

So, 1000 kJ energy required amount of C_2H_6 = \frac{1000}{52}=19.23g

and,

As, 49 kJ energy required amount of C_4H_{10} = 1 g

So, 1000 kJ energy required amount of C_4H_{10} = \frac{1000}{49}=20.41g

<u>Part 2 :</u>

Now we have to calculate the number of moles of each fuel (C_2H_6)\text{ and }(C_4H_{10}).

Molar mass of C_2H_6 = 30 g/mole

Molar mass of C_4H_{10} = 58 g/mole

\text{ Moles of }C_2H_6=\frac{\text{ Mass of }C_2H_6}{\text{ Molar mass of }C_2H_6}=\frac{19.23g}{30g/mole}=0.641moles

and,

\text{ Moles of }C_4H_{10}=\frac{\text{ Mass of }C_4H_{10}}{\text{ Molar mass of }C_4H_{10}}=\frac{20.41g}{58g/mole}=0.352moles

<u>Part 3 :</u>

Now we have to write down the balanced chemical equation for the combustion of the fuels.

The balanced chemical reaction for combustion of C_2H_6 is:

C_2H_6+\frac{7}{2}O_2\rightarrow 2CO_2+3H_2O

and,

The balanced chemical reaction for combustion of C_4H_{10} is:

C_4H_{10}+\frac{13}{2}O_2\rightarrow 4CO_2+5H_2O

<u>Part 4 :</u>

Now we have to calculate the number of moles of CO_2 produced by burning each fuel to produce 1000 kJ.

C_2H_6+\frac{7}{2}O_2\rightarrow 2CO_2+3H_2O

From this we conclude that,

As, 1 mole of C_2H_6 react to produce 2 moles of CO_2

As, 0.641 mole of C_2H_6 react to produce 0.641\times 2=1.28 moles of CO_2

and,

C_4H_{10}+\frac{13}{2}O_2\rightarrow 4CO_2+5H_2O

From this we conclude that,

As, 1 mole of C_4H_{10} react to produce 4 moles of CO_2

As, 0.352 mole of C_4H_{10} react to produce 0.352\times 4=1.41 moles of CO_2

So, the fuel that emitting least amount of CO_2 is C_2H_6

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The carbon atom has a single bond to the atom on its left side while having a triple bond on the nitrogen atom on the right side.
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Answer:

Explanation:

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kakasveta [241]

Answer:

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Explanation:

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<em>#</em><em>C</em><em>a</em><em>r</em><em>r</em><em>y</em><em>O</em><em>n</em><em>L</em><em>e</em><em>a</em><em>r</em><em>n</em><em>i</em><em>n</em><em>g</em>

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