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Burka [1]
3 years ago
11

How many miles are 248 grams of phosphorus (P4)? How many atoms are there in the same amount of phosphorus?

Chemistry
1 answer:
AnnZ [28]3 years ago
7 0

Answer:

2 moles, 1.2044 * 10²⁴ particles/atoms

Explanation:

P4 = 4(30.974) = 123.896

To find the moles, we need to divide grams/the atomic mass..

248/123.896 = 2.001678827 moles or just 2 moles

To convert from moles to atoms, we need to multiply by avogadro's number (6.022*10²³)

After plugging this into out calculator, we have 1.2044E24, which basically means 1.2044 * 10²⁴ particles/atoms

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Enter your answer in the provided box.S(rhombic) + O2(g) → SO2(g) ΔHo rxn= −296.06 kJ/molS(monoclinic) + O2(g) → SO2(g) ΔHo rxn=
IgorC [24]

Answer: \Delta H^0=+0.3kJ/mol.

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

S_{rhombic}+O_2(g)\rightarrow SO_2(g)    \Delta H^0_1=-296.06kJ   (1)

S_{monoclinic}+O_2(g)\rightarrow SO_2(g)/tex] [tex]\Delta H^0_2=-296.36kJ  (2)

The final reaction is:  

S_{rhombic}\rightarrow S_{monoclinic}  \Delta H^0_3=?   (3)

By subtracting (1) and (2)

\Delta H^0_3=\Delta H^0_1-\Delta H^0_2=-296.06kJ-(-296.36kJ)=0.3kJ

Hence the enthalpy change for the transformation S(rhombic) → S(monoclinic) is 0.3kJ

3 0
3 years ago
How many moles of cacl2 are needed to make 0.250 liters of 2.250m solution
ANTONII [103]

Answer:

.562 mol (with respect to signifigant figures)

Explanation:

to find moles we must use concentration to cancel liters.

2.250 mol/L x .250 L = .5625 mol

8 0
3 years ago
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