Simplify 6x+9/15x^2 divided by 16x-12/10^4

Determine a pair of angles (one positive and one negative) in degree measure coterminal to the angle 117°.

andre [41]

Answer:

Option B.

Step-by-step explanation:

When we have an angle A, in degrees, the coterminal angles are all the angles that can be written as:

B = A + n*360°

Where n is a positive or a negative integer (if n = 0, then B = A, which means that A is coterminal with itself, which is trivial).

Now we want to find two coterminal angles to 117°, such that one is positive and the other negative.

Then we can do:

for the positive one, use n = 1.

B = 117° + 1*360° = 477°

For the negative one, use n = -1

B = 117° - 1*360° = -243°

Then the two angles are 477° and -243°

The correct option is B.

4 0

3 years ago

Read 2 more answers

Evaluate the following integral using trigonometric substitution.

wariber [46]

Answer:

Step-by-step explanation:

1. Given the integral function $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ , using trigonometric substitution, the substitution that will be most helpful in this case is substituting x as $asin \theta$ i.e $x = a sin\theta$ .

All integrals in the form $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ are always evaluated using the substitute given where 'a' is any constant.

From the given integral, $\int\limits {7\sqrt{49-x^{2} } } \, dx = \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx$ where a = 7 in this case.

The substitute will therefore be $x = 7 sin\theta$

2.) Given $x = 7 sin\theta$

$\frac{dx}{d \theta} = 7cos \theta$

cross multiplying

$dx = 7cos\theta d\theta$

3.) Rewriting the given integral using the substiution will result into;

$\int\limits {7\sqrt{49-x^{2} } } \, dx \\= \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -(7sin\theta)^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -49sin^{2}\theta } } \, dx\\= \int\limits {7\sqrt{49(1-sin^{2}\theta)} } } \, dx\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, dx\\since\ dx = 7cos\theta d\theta\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, 7cos\theta d\theta\\= \int\limits {7\{7(cos\theta)} }}} \, 7cos\theta d\theta\\$

$= \int\limits343 cos^{2} \theta \, d\theta$

8 0

3 years ago

WILL GGIVE BRAINLIEST!!!

Citrus2011 [14]

(3x+6)(2x^2), using the distributive property, equals 2x^2*3x+2x^2*6. We multiply the 2 with the coefficients and add a power of x if multiplied by x, getting 6x^3+12x^2

3 0

3 years ago

Anyone know the answer?

FrozenT [24]

I legit can’t see it

8 0

3 years ago

What is the imaginary part of the number 9?

KengaRu [80]

Answer:

Step-by-step explanation:

The imaginary number has form:

a + bi

a - real part

bi - imaginary part

i - imaginary unit (i = √-1)

We have the number 9.

9 is a real part

An imaginary part is equal 0.

Therefore the imaginary part of number 9 is 0i.

4 0

3 years ago