MCE = 360 - (150 + 70 + 50)
mCE = 360 - 270
mCE = 90
<CDE = 1/2(mBE + mCE)
<CDE = 1/2(150 + 90)
<CDE = 1/2(240)
<CDE = 120
answer
<CDE = 120°
Answer:
36
Step-by-step explanation:
6 x 2= 12
12 x 3= 36
<span>Answer:
MgF2 ====⇒ Mg+2 + 2F-
Ksp = [Mg+2][F-]^2
Let S = molar solubility of MgF2
[Mg+2] = S ; [F-] = 2s
Since the [F-] is initially 0.40 M, then [F-] = 0.40 + 2S
6.4 x 10^-9 = (S) (0.40 + 2S)^2 ; one can neglect the 2S in the 0.40 + 2S expression since it is very, very small compared to the 0.40 already present.
6.4 x 10^-9 = S(0.40)^2
S = 4.0 x 10^-8
Molar solubility = 4.0 x 10^-8</span>
Answer:
Here is your answer
Step-by-step explanation:
B) 2x + 5 = 7
vertical line
C) 2x - y = 6
oblique line
D) 3y + 9 = 0
horizontal line
It would be $2.6 (or $2.60) per pound.
