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4 years ago

PLEASE HURRY!!! 30 POINTS

Mathematics

2 answers:

mixas84 [53]4 years ago

6 0

The answer is 23.6 if I pretty sure

erik [133]4 years ago

5 0

The answer is 23.6! 1 pint is equal to 0.473176, and 50 is equal to 23.6! Hope this helps :)

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Margo can purchase tile at a store for $0.59 per tile and rent a tile saw for $14. At another store she can

netineya [11]

lmk if this helps

: • 1:33)= 8 • x

7.998 = 8x

1 = x

•59x + 32 = 1.39x

32 = .8x

40 = x

8 0

3 years ago

Read 2 more answers

ALL I NEED IS THE EQATION!

valkas [14]

Answer:

b=0.25×80

b=1/4×80

Step-by-step explanation:

We know that bike equals 25%, so we just need to find 25% of 80.

b=0.25×80.

8 0

3 years ago

Read 2 more answers

PLEASE ANSWER + BRAINLIEST!!

marshall27 [118]

X^4 + 2x^2 - 24
= (x^2 + 6)(x^2 - 4)
= (x^2 + 6)(x - 2)(x + 2)

x^4 - 9x^2 + 18
= (x^2 - 6)(x^2 - 3)

7 0

3 years ago

A new post-surgical treatment is being compared with a standard treatment. Seven subjects receive the new treatment, while seven

a_sh-v [17]

Answer:

$(17.714-28.714) -2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -19.745$

$(17.714-28.714) +2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -2.255$

Step-by-step explanation:

For this case we have the following info given:

Treatment: 12 13 15 19 20 21 24

Control: 18 23 24 30 32 35 39

We can find the sample mean and deviations with the the following formulas:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s =\sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}$

And repaplacing we got:

$\bar X_T = 17.714$ the sample mean for treatment

$\bar X_C = 28.714$ the sample mean for treatment

$s_T= 4.461$ the sample deviation for treatment

$s_C= 7.387$ the sample deviation for control

$n_T= n_C= 7$ the sample size for each sample

The degrees of freedom are given by:

$df= 7+7-2= 12$

The confidence interval for the difference of means is given by:

$(\bar X_T -\bar X_C) \pm t_{\alpha/2} \sqrt{\frac{s^2_T}{n_T} +\frac{s^2_C}{n_C}}$

The confidence is 98% so then the significance is $\alpha=0.02$ and $\alpha/2 =0.01$ . Then the critical value would be:

$t_{\alpha/2}=2.681$

And replacing we got:

$(17.714-28.714) -2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -19.745$

$(17.714-28.714) +2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -2.255$

4 0

4 years ago

-2.1 1.3 1.5 -1.2 -0.6 0.9 3.4 from least to greatest

storchak [24]

-2.1 , -1.2 , -0.6, 0.9, 1.3 , 1.5 , 3.4

Hope this helps!

4 0

4 years ago

Read 2 more answers