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frutty [35]
3 years ago
9

For the equation 17h+6=40, select the appropriate property of equality to move the constant term to the right side of the equati

on.(20pt) A. Division Property of Equality- B. Subtraction Property of Equality - C. Multiplication Property of Equality- D. Addition Property of Equality
Mathematics
1 answer:
jasenka [17]3 years ago
4 0

Answer:

Option B.

Step-by-step explanation:

The given equation is

17h+6=40

We need to find the property of equality to move the constant term to the right side of the equation.

In the given equation 6 is the constant term on the left side.

Using subtraction property of equality, subtract 6 from both sides.

17h+6-6=40-6

17h=34

So, the appropriate property of equality to move the constant term to the right side of the equation is Subtraction Property of Equality.

Therefore, the correct option is B.

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Javier volunteers in community events each month. He does not do more than five events in a month. He attends exactly five event
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Answer:

The probability of Javier volunteers for less than three a month is 25%

Step-by-step explanation:

According to the questions,

The probability of Javier to attend exactly 5 events :-

P ( x = 5 ) = 25% = \frac{1}{4}

The probability of Javier to attend exactly 4 events :-

P ( x = 4 ) = \frac{1}{4}

The probability of Javier to attend exactly 3 events :-

P ( x = 3 ) = \frac{1}{4}

The probability of Javier to attend exactly 2 events :-

P ( x = 2 ) = \frac{3}{20}

The probability of Javier to attend exactly 1 events :-

P ( x = 1 ) = \frac{1}{20}

The probability of Javier to attend no events :-

P ( x = 0 ) = \frac{1}{20}

Now we have to calculate the probability of Javier volunteers for less than three P ( x < 3 ).

P ( x < 3 ) = P ( x = 0 ) + P ( x = 1 ) + P ( x = 2 )

P ( x < 3 ) = \frac{1}{20} + \frac{1}{20} + \frac{3}{20}   = \frac{1 + 1 + 3}{20}  = \frac{5}{20}  = \frac{1}{4}   = 0.25 = 25 %.

8 0
3 years ago
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