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REY [17]
3 years ago
7

Can someone help me, i am very confused, i need to find the volume of the figure put i dont know how

Mathematics
1 answer:
Hoochie [10]3 years ago
3 0
Ok so what you need to know about an octahedron is it's basically two square pyramids stacked on top of each other (one is upside down of course).

The formula for volume of a pyramid is Bh/3.
Base= 8*8=64
Height= 3 each
64*3/3= 64 mm^3 per pyramid.

64*2=128 mm^3 for the octahedron

Final answer: 128 mm^3
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If we assume the club membership includes

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then the blanks in the Juniors circle must be filled in with 6 and 8 (with the 8 going in the overlap with girls). The remaining blank in the Girls circle must be filled in with 12, the number of senior girls. The blank outside both circles is the number of senior boys (members who are not juniors and not girls), 16.

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3 years ago
The coordinates of the vertices of ΔPQR are (–2, –2), (–6, –2), and (–6, –5).
melamori03 [73]
<h3>Answer:</h3>

Yes, ΔPʹQʹRʹ is a reflection of ΔPQR over the x-axis

<h3>Explanation:</h3>

The problem statement tells you the transformation is ...

... (x, y) → (x, -y)

Consider the two points (0, 1) and (0, -1). These points are chosen for your consideration because their y-coordinates have opposite signs—just like the points of the transformation above. They are equidistant from the x-axis, one above, and one below. Each is a <em>reflection</em> of the other across the x-axis.

Along with translation and rotation, <em>reflection</em> is a transformation that <em>does not change any distance or angle measures</em>. (That is why these transformations are all called "rigid" transformations: the size and shape of the transformed object do not change.)

An object that has the same length and angle measures before and after transformation <em>is congruent</em> to its transformed self.

So, ... ∆P'Q'R' is a reflection of ∆PQR over the x-axis, and is congruent to ∆PQR.

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