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Lena [83]
3 years ago
7

The coordinates of the vertices of ΔPQR are (–2, –2), (–6, –2), and (–6, –5).

Mathematics
1 answer:
melamori03 [73]3 years ago
6 0
<h3>Answer:</h3>

Yes, ΔPʹQʹRʹ is a reflection of ΔPQR over the x-axis

<h3>Explanation:</h3>

The problem statement tells you the transformation is ...

... (x, y) → (x, -y)

Consider the two points (0, 1) and (0, -1). These points are chosen for your consideration because their y-coordinates have opposite signs—just like the points of the transformation above. They are equidistant from the x-axis, one above, and one below. Each is a <em>reflection</em> of the other across the x-axis.

Along with translation and rotation, <em>reflection</em> is a transformation that <em>does not change any distance or angle measures</em>. (That is why these transformations are all called "rigid" transformations: the size and shape of the transformed object do not change.)

An object that has the same length and angle measures before and after transformation <em>is congruent</em> to its transformed self.

So, ... ∆P'Q'R' is a reflection of ∆PQR over the x-axis, and is congruent to ∆PQR.

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Option 3

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<h3><u>Given</u>;</h3>
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y + 16 = 8(x + 2)

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Here, L.H.S = R.H.S

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Answer:

Check pdf

Step-by-step explanation:

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