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postnew [5]
4 years ago
12

In an annual sales contest, Lisa sold $188, $212, $214, $196, and $200 worth of products in the first five years. In order to qu

alify for the grand prize, she must average at least $205 over six years. What is the least amount she must sell in the sixth year in order to qualify?
Mathematics
2 answers:
nikdorinn [45]4 years ago
6 0
The answer is 220 at least. Here's how it goes
Multiply $205 with 6 and subtract the sum of the five years from it. That's how I think and I hope it helps
Sphinxa [80]4 years ago
4 0

Answer: $220

Step-by-step explanation:

Formula to find Average :

\text{Average}=\dfrac{\text{Sum of all observations}}{\text{Total number observations}}

Let x be the  amount she must sell in the sixth year in order to qualify.

Given : In an annual sales contest, Lisa sold $188, $212, $214, $196, and $200 worth of products in the first five years.

Then, the average over six years would be

\text{Average}=\dfrac{188+212+214+196+200+x}{6}

In order to qualify for the grand prize, she must average at least $205 over six years.

i.e. \text{Average}=\dfrac{188+212+214+196+200+x}{6}\geq205

\Rightarrow\ \dfrac{1010+x}{6}\geq205

\Rightarrow\ 1010+x\geq205\times6

\Rightarrow\ 1010+x\geq1230

\Rightarrow\ x\geq1230-1010

\Rightarrow\ x\geq220

Hence, the least amount she must sell in the sixth year in order to qualify= $220

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Q3. a. Simplify the following ratios.<br> 360:120:60
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Answer:

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Step-by-step explanation:

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Answer:

The cube root of given expression is 6x^3y^6.

Step-by-step explanation:

The given expression is

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It can be written as

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\sqrt[3]{216x^9y^{18}}=\sqrt[3]{6^3(x^3)^3(y^6)^{3}}

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