P/2-5 cuando p=14 No le entiendo y debo contestar
1 answer:
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Answer:
The dimensions of the original rectangle are Length =12cm, Width=8cm
Step-by-step explanation
Let the length of the rectangle be x
Let the width of the rectangle be y
The perimeter of a rectangle is 40cm.
2(x+y)=40
Divide both sides by 2
x+y=20
If the length were doubled(2x) and the width halved(y/2), the perimeter would be increased by 16cm,i.e.(40+16)cm
Therefore:
Divide both sides by 2
From the first equation, x=20-y.
Substitute x=20-y into
<u>Answer:</u>
A = 70
B = 90
<u>Step-by-step explanation:</u>
We know that Car A travels 20 mph faster than Car B.
Assuming the speed of Car B to be x and the speed of Car A to be x+20, we can write:
Taking the reciprocal of both sides to make x the subject:
---> speed of Car A
Finding the speed of Car B:
Therefore, the speed of Car A = 70 and the speed of Car B = 90.